009C Sample Final 1, Problem 6

Find the Taylor polynomial of degree 4 of $f(x)=\cos ^{2}x$ at $a={\frac {\pi }{4}}$.

Foundations:
The Taylor polynomial of $f(x)$ at $a$ is
$\sum _{n=0}^{\infty }c_{n}(x-a)^{n}$ where $c_{n}={\frac {f^{(n)}(a)}{n!}}.$

Solution:

Step 1:
First, we make a table to find the coefficients of the Taylor polynomial.
$n$ $f^{(n)}(x)$ $f^{(n)}(a)$ ${\frac {f^{(n)}(a)}{n!}}$ $0$ $\cos ^{2}x$ ${\frac {1}{2}}$ ${\frac {1}{2}}$ $1$ $-2\cos x\sin x$ $-1$ $-1$ $2$ $2\sin ^{2}x-2\cos ^{2}x$ $0$ $0$ $3$ $8\sin x\cos x$ $4$ Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {2}{3}}} $4$ $8\cos ^{2}x-8\sin ^{2}x$ $0$ $0$

Step 2:
Since $c_{n}={\frac {f^{(n)}(a)}{n!}},$ the Taylor polynomial of degree 4 of $f(x)=\cos ^{2}x$ is
$T_{4}(x)={\frac {1}{2}}+-1{\bigg (}x-{\frac {\pi }{4}}{\bigg )}+{\frac {2}{3}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}^{3}.$

Final Answer:
Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {1}{2}}+-1{\bigg (}x-{\frac {\pi }{4}}{\bigg )}+{\frac {2}{3}}{\bigg (}x-{\frac {\pi }{4}}{\bigg )}^{3}}

Return to Sample Exam