Difference between revisions of "Math 22 Graph of Equation"
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|We need to know the radius and the center in order to write the equation. The center is given at <math>(3,4)</math>. It is left to find the radius. | |We need to know the radius and the center in order to write the equation. The center is given at <math>(3,4)</math>. It is left to find the radius. | ||
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− | |Radius is the distance | + | |Radius is the distance between the center and a point on the circle. So, radius <math>r</math> is the distance between <math>(2,1)</math> and <math>(3,4)</math>. |
+ | |- | ||
+ | |So, <math>r=\sqrt{(2-3)^2+(1-4)^2}{</math> | ||
|} | |} | ||
Revision as of 07:29, 13 July 2020
The Graph of an Equation
The graph of an equation is the set of all points that are solutions of the equation.
In this section, we use point-plotting method. With this method, you construct a table of values that consists of several solution points of the equation
For example, sketch the graph of . We can construct the table below by plugging points for .
x | 0 | 1 | 2 | 3 |
y=2x+1 | 1 | 3 | 5 | 7 |
So, we can sketch the graph from those order pairs.
Intercepts of a Graph
Some solution points have zero as either the -coordinate or the -coordinate. These points are called intercepts because they are the points at which the graph intersects the - or -axis.
To find -intercepts, let be zero and solve the equation for . To find -intercepts, let be zero and solve the equation for .
Example Find the x-intercepts and y-intercepts of the graph
Solution: |
---|
x-intercept: Let , so , hence , therefore, or |
y-intercept: Let , so |
Answer: and are x-intercepts |
is y-intercept |
Circles
The standard form of the equation of a circle is The point is the center of the circle, and the positive number is the radius of the circle
In general, to write an equation of a circle, we need to know radius and the center .
Example Given that the point is on the circle centered at (3,4). Find the equation of a circle.
Solution: |
---|
We need to know the radius and the center in order to write the equation. The center is given at . It is left to find the radius. |
Radius is the distance between the center and a point on the circle. So, radius is the distance between and . |
So, Failed to parse (syntax error): {\displaystyle r=\sqrt{(2-3)^2+(1-4)^2}{} |
Notes
Distance between and can be calculated by using
This page were made by Tri Phan