# Math 22 Integration by Parts and Present Value

## Integration by Parts

Let and be differentiable functions of .Failed to parse (unknown function "\dv"): {\displaystyle \int u \dv=uv-\int v \du}

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From Math Wiki

Let $u$ and $v$ be differentiable functions of $x$.Failed to parse (unknown function "\dv"): {\displaystyle \int u \dv=uv-\int v \du}

**This page were made by Tri Phan**