Find the derivative: 
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(Note: You do not need to simplify the derivative after finding it.)
| Foundations:
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| This problem requires some more advanced rules of differentiation. In particular, it needs
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| The Chain Rule: If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f}
and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g}
are differentiable functions, then
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Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (f\circ g)'(x) = f'(g(x))\cdot g'(x).}
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The Quotient Rule: If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f}
and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g}
are differentiable functions and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g(x) \neq 0}
, then
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Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(\frac{f}{g}\right)'(x) = \frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{\left(g(x)\right)^2}. }
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Solution:
| Find the derivative of the denominator:
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| We need to use the chain rule, where the inner function is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^3 + 7}
and the outer function is natural log:
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- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \left[\ln(x^{3}+7)\right]' & = & {\displaystyle \frac{1}{x^{3}+7}\cdot3x^{2}}\\ \\ & = & {\displaystyle \frac{3x^{2}}{x^{3}+7}.} \end{array}}
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| Apply the Quotient Rule:
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- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{array}{rcl} \left[{\displaystyle \frac{\ln(x^{3}+7)}{x^{4}+2x^{2}}} \right]' & = & {\displaystyle \frac{\left[\ln(x^{3}+7)\right]'\cdot\left(x^{4}+2x^{2}\right)-\left(x^{4}+2x^{2}\right)'\cdot\ln(x^{3}+7)}{\left(x^{4}+2x^{2}\right)^{2}}}\\ \\ & = & {\displaystyle \frac{\frac{3x^{2}}{x^{3}+7}\cdot\left(x^{4}+2x^{2}\right)-\left(4x^{3}+4x\right)\cdot\ln(x^{3}+7)}{\left(x^{4}+2x^{2}\right)^{2}}}.\\ \\ \end{array}}
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| Final Answer:
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- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left[\frac{\ln(x^{3}+7)}{x^{4}+2x^{2}}\right]'\,=\,\frac{\frac{3x^{2}}{x^{3}+7}\cdot\left(x^{4}+2x^{2}\right)-\left(4x^{3}+4x\right)\cdot\ln(x^{3}+7)}{\left(x^{4}+2x^{2}\right)^{2}}.}
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