Difference between revisions of "022 Exam 2 Sample B, Problem 4"
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(Created page with "<span class="exam"> '''Set up the equation to solve. You only need to plug in the numbersnot solve for the particular values!''' <span class="exam">What is the present value...") 

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−  We are given all the pieces required. We begin with <math style="verticalalign: 5%;">$3000</math> of principal, and compound  +  We are given all the pieces required. We begin with <math style="verticalalign: 5%;">$3000</math> of principal, and compound quarterly, or <math style="verticalalign: 5%;">4</math> times per year. Using the formula in 'Foundations', the equation for the account value is 
    
    
−  ::<math>A\,=\,P\left(1+\frac{r}{n}\right)^{nt}\,=\,3000\left(1+\frac{0.  +  ::<math>A\,=\,P\left(1+\frac{r}{n}\right)^{nt}\,=\,3000\left(1+\frac{0.06}{4}\right)^{4\cdot 8}.</math> 
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−  ::<math>A\,=\,Pe^{rt}\,=\,3000e^{0.  +  ::<math>A\,=\,Pe^{rt}\,=\,3000e^{0.06\cdot 8}.</math> 
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−  ::(a) <math style="verticalalign: 80%;">A\,=\,3000\left(1+\frac{0.  +  ::(a) <math style="verticalalign: 80%;">A\,=\,3000\left(1+\frac{0.06}{4}\right)^{4\cdot 8}.</math> 
    
    
−  ::(b) <math style="verticalalign: 0%;">A\,=\,Pe^{rt}\,=\,3000e^{0.  +  ::(b) <math style="verticalalign: 0%;">A\,=\,Pe^{rt}\,=\,3000e^{0.06\cdot 8}.</math> 
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[[022_Exam_2_Sample_B'''<u>Return to Sample Exam</u>''']]  [[022_Exam_2_Sample_B'''<u>Return to Sample Exam</u>''']] 
Revision as of 17:45, 15 May 2015
Set up the equation to solve. You only need to plug in the numbersnot solve for the particular values!
What is the present value of $3000, paid 8 years from now, in an investment that pays 6%interest,
 (a) compounded quarterly?
 (b) compounded continuously?
Foundations: 

The primary purpose of this problem is to demonstrate that you understand the difference between continuous compounding and compounding on an interval of time. When we compound on an interval, say monthly, the value in the account only changes at the end of each interval. In other words, there is no interest accrued for a week or a day. As a result, we use the formula 

where is the value of the account, is the principal (original amount invested), is the annual rate and is the number of compoundings per year. The value of is for compounding daily, for compounding weekly, and for compounding monthly. As a result, the exponent , where is the time in years, is the number of compounding periods where we actually earn interest. Similarly, is the rate per compounding period (the annual rate divided by the number of compoundings per year). 
For example, if we compound monthly for years at a rate, we would compound times, once per month, at a rate of per monthly period. Notice that we always use the decimal version for interest rates when using these equations. 
On the other hand, interest compounded continuously earns rate in just that way  continuously. I can have any value I want for time , and the total amount in the account will change with each and every second. Therefore, we express the account value as 

Notice that in both formulas, the value at the initial time is just our initial investment . The goal in the two parts of this problem is to choose the correct equation for each. 
(a): 

We are given all the pieces required. We begin with of principal, and compound quarterly, or times per year. Using the formula in 'Foundations', the equation for the account value is 

(b): 

Again, we need to apply the formula from foundations to find 

Final Answer: 


