008A Sample Final A, Question 3

From Math Wiki
Revision as of 14:44, 28 April 2015 by MathAdmin (talk | contribs)
Jump to navigation Jump to search

Question: a) Find the vertex, standard graphing form, and X-intercept for

                  b) Sketch the graph. Provide the focus and directrix.

Note: In this problem, what is referred to as standard graphing form is the vertex form, in case you search on the internet.

1) What type of function are we asking you to graph (line, parabola, circle, etc.)?
2) What is the process for transforming the function into the standard graphing form?
3) After we have the standard graphing form how do you find the X-intercept, and vertex?
4) Moving on to part b) How do we find a point on the graph?
5) From the standard graphing form how do we obtain relevant information about the focus and directrix?
1) The function is a parabola. Some of the hints: We are asked to find the vertex, and directrix. Also only one variable, of x and y, is squared.
2) First we complete the square. Then we divide by the coefficient of x.
3) To find the X-intercept, replace y with 0 and solve for x. Since the parabola is in standard graphing form, the vertex of is (h, k).
4) To find a point, we can either use the symmetry of a parabola or plug in another value for x.
5) From the equation , we use the equation to find p. P is both the distance from the vertex to the focus and the distance from the vertex to the directrix.


Step 1:
There are two ways to obtain the standard graphing form.
Regardless of the method the first step is the same: subtract 2 from both sides to yield
Method 1:
Divide both sides by -3 to make the coefficient of , 1. This means
Complete the square to get
Multiply both sides by -3 so , and simplify the left side to yield
Method 2:
Instead of dividing by -3 we factor it out of the right hand side to get .
Now we complete the square inside the parenthesis and add -3 to the left hand side resulting in
Step 2:
Since the parabola is in standard graphing form we can read off the vertex, which is (2, -1).
We get the X-intercept by replacing y with 0 and solving for x. So , and the X-intercept is (2, 0).
Step 3:
Now we need the value of p using the relation , where a = -3.
So , and .
Step 4:
Since , the parabola opens left. Since the focus is inside the parabola, and p tells us the focus is from the vertex, the focus is at .
We also know that the directrix is a vertical line on the outside of the parabola with the distance from the directrix to the vertex being p. Thus the directrix is
Final Answer:
Vertex: (2, -1), standard graphing form: , X-intercept: (2, 0), focus: , directrix:

8A Sample Final A, Q 3.png

Return to Sample Exam