# 008A Sample Final A, Question 2

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Question: Find f(5) for ${\displaystyle f(x)=\log _{3}(x)-1}$, which is the function from problem 1.

Foundations:
How would you find f(5) if f(x) = 2x + 1 instead?
Answer: we replace every occurrence of x with a 5. So

${\displaystyle {\begin{array}{rcl}f(5)&=&2(5)+1\\&=&11\end{array}}}$

Solution:

Step 1:
Replace any occurrence of x by 5, so

${\displaystyle {\begin{array}{rcl}f(5)&=&\log _{3}(5+3)-1\\&=&\log _{3}(8)-1\end{array}}}$

${\displaystyle \log _{3}(8)-1}$