007B Sample Midterm 3, Problem 4 Detailed Solution
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Find the volume of the solid obtained by rotating the region bounded by and about the axis. Sketch the graph of the region and a typical disk element.
| Background Information: |
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1. You can find the intersection points of two functions, say |
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by setting and solving for |
| 2. The volume of a solid obtained by rotating an area around the -axis using the washer method is given by |
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where is the inner radius of the washer and is the outer radius of the washer. |
Solution:
| Step 1: |
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| First, we need to find the intersection points of Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle y={\sqrt {\sin x}}} and |
| To do this, we need to solve |
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0={\sqrt {\sin x}}.} |
| Squaring both sides, we get Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0=\sin x.} |
| The solutions to this equation in the interval are |
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| Now, the graph of the region is below. |
| Additionally, we are going to be using the washer/disk method. |
| Below, we show a typically disk element. |
| (Insert graph) |
| Step 2: |
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| The volume of the solid using the disk method is |
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{array}{rcl}\displaystyle {V}&=&\displaystyle {\int _{0}^{\pi }\pi ({\sqrt {\sin x}})^{2}~dx}\\&&\\&=&\displaystyle {\int _{0}^{\pi }\pi \sin x~dx}\\&&\\&=&\displaystyle {-\pi \cos x{\bigg |}_{0}^{\pi }}\\&&\\&=&\displaystyle {-\pi \cos(\pi )+\pi \cos(0)}\\&&\\&=&\displaystyle {2\pi .}\end{array}}} |
| Final Answer: |
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| See Step 1 for graph. |
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle V=2\pi } |