Question Graph the following,
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -x^2+4y^2-2x-16y+11=0}
| Foundations:
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| 1) What type of function is this?
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| 2) What can you say about the orientation of the graph?
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| Answer:
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| 1) Since both x and y are squared it must be a hyperbola or an ellipse. We can conclude that the graph is a hyperbola since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^2}
and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y^2}
have the different signs, one negative and one positive.
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| 2) Since the Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y^2}
is positive, the hyperbola opens up and down.
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Solution:
| Step 1:
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| We start by completing the square twice, once for x and once for y. After completing the squares we end up with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle -(x + 1)^2 +4(y - 2)^2 = 4}
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| Common Mistake: When completing the square we will end up adding numbers inside of parenthesis. So make sure you add the correct value to this other side. In this case we add -1, and 16 for completing the square with respect to x and y, respectively.
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| Step 2:
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| Now that we have the equation that looks like an ellipse, we can read off the center of the ellipse, (0, -1).
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| From the center mark the two points that are 3 units left, and three units right of the center.
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| Then mark the two points that are 2 units up, and two units down from the center.
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| Final Answer:
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| The four vertices are: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (-3, -1), (3, -1), (0, 1) \text{ and } (0, -3)}
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