Math 22 Derivatives of Logarithmic Functions
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Derivative of the Natural Logarithmic Function
Let be a differentiable function of . 1.Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {d}{dx}}[\ln x]={\frac {1}{x}}} for 2.Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {d}{dx}}[\ln u]={\frac {1}{u}}{\frac {du}{dx}}} for
Exercises Find the derivative of the function
a) Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle f(x)=\ln(7x)}
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| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle f'(x)={\frac {1}{7x}}(7x)'={\frac {1}{7x}}7={\frac {1}{x}}} |
b) Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle f(x)=\ln(x^{8})}
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| Solution 1: Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle f'(x)={\frac {1}{x^{8}}}(x^{8})'={\frac {8x^{7}}{x^{8}}}={\frac {8}{x}}} |
| Solution 2: , so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x)=8\frac{1}{x}=\frac{8}{x}} |
c) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x)=\ln (4-x^2)}
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| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x)=\frac{1}{4-x^2}(4-x^2)'=\frac{1}{4-x^2}(-2x)=\frac{-2x}{4-x^2}} |
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