009A Sample Final A, Problem 6
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6. Find the vertical and horizontal asymptotes of the function
| Foundations: |
|---|
| Vertical asymptotes occur whenever the denominator of a rational function goes to zero, and it doesn't cancel from the numerator. |
| On the other hand, horizontal asymptotes represent the limit as goes to either positive or negative infinity. |
Solution:
| Vertical Asymptotes: |
|---|
| Setting the denominator to zero, we have |
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 0=10x-20=10(x-2),} |
| which has a root at This is our vertical asymptote. |
| Horizontal Asymptotes: |
|---|
| More work is required here. Since we need to find the limits at , we can multiply our by |
This expression is equal to for positive values of , and is equal to for negative values of . Since multiplying by an expression equal to doesn't change the limit, we will add a negative sign to our fraction when considering the limit as goes to . Thus, |
Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \lim _{x\rightarrow \pm \infty }{\frac {\sqrt {4x^{2}+3}}{10x-20}}\,\,\cdot \,\,\pm {\frac {\sqrt {\frac {1}{x^{2}}}}{\,\,\,{\frac {1}{x}}}}=\lim _{x\rightarrow \pm \infty }\pm {\frac {\sqrt {{\frac {4x^{2}}{x^{2}}}+{\frac {3}{x^{2}}}}}{{\frac {10x}{x}}-{\frac {20}{x}}}}=\lim _{x\rightarrow \pm \infty }\pm {\frac {\sqrt {4+{\frac {3}{x^{2}}}}}{10-{\frac {20}{x}}}}=\pm {\frac {2}{10}}=\pm {\frac {1}{5}}} |
Thus, we have a horizontal asymptote at Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle y=-1/5} on the left (as goes to ), and a horizontal asymptote at on the right (as goes to ). |