Find the following limits:
(a) If lim x → 3 ( f ( x ) 2 x + 1 ) = 2 , {\displaystyle \lim _{x\rightarrow 3}{\bigg (}{\frac {f(x)}{2x}}+1{\bigg )}=2,} find lim x → 3 f ( x ) . {\displaystyle \lim _{x\rightarrow 3}f(x).}
(b) Evaluate lim x → 2 2 − x x 2 − 4 . {\displaystyle \lim _{x\rightarrow 2}{\frac {2-x}{x^{2}-4}}.}
(c) Find lim x → 0 tan ( 4 x ) sin ( 6 x ) . {\displaystyle \lim _{x\rightarrow 0}{\frac {\tan(4x)}{\sin(6x)}}.}
Solution
Detailed Solution
Return to Sample Exam
find 
