Find the antiderivative of
| Foundations:
|
| This problem requires three rules of integration. In particular, you need
|
Integration by substitution (u - sub): If is a differentiable functions whose range is in the domain of , then
|
|
| We also need our power rule for integration:
|
for ,
|
Solution:
| Step 1:
|
Use a U-substitution with This means Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle du=3dx}
, and after substitution we have
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int \left(3x+2\right)^{4}dx=\int u^{4}du}
|
| Step 2:
|
We can no apply the power rule for integration:
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int u^{4}du={\frac {u^{5}}{5}}}
|
| Step 3:
|
| Since our original function is a function of x, we must substitute x back into the result from problem 2:
|
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {u^{5}}{5}}={\frac {(3x+2)^{5}}{5}}}
|
| Step 4:
|
| As will all indefinite integrals, don't forget the "+C" at the end.
|
| Final Answer:
|
| Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int \left(3x+2\right)^{5}dx\,=\,{\frac {(3x+2)^{5}}{5}}+C}
|
Return to Sample Exam