Math 22 Chain Rule

The Chain Rule

 If $y=f(x)$ is a differentiable function of $u$ and $u=g(x)$ is a 
 differentiable function of $x$, then $y=f(g(x))$ is a differentiable function 
 of $x$ and
 
 ${\frac {dy}{dx}}={\frac {dy}{du}}\cdot {\frac {du}{dx}}$
 
 In another word, ${\frac {d}{dx}}[f(g(x))]=f'(g(x))\cdot g'(x)$

Example: Find derivative of

1) $f(x)={\sqrt {x^{2}+3x-4}}$

Solution:
$f(x)=f(x)={\sqrt {x^{2}+3x-4}}=(x^{2}+3x-4)^{\frac {1}{2}}$
$f'(x)={\frac {1}{2}}\cdot (x^{2}+3x-4)^{{\frac {1}{2}}-1}{\frac {d}{dx}}[x^{2}+3x-4]$
<math=(x^2+3x-4)^{\frac{-1}{2}}(2x+3)

2) $f(x)=(x^{2}+1)^{1}00$

Solution:
$f'(x)=100(x^{2}+1)^{9}9{\frac {d}{dx}}[x^{2}+1]$
$=100(x^{2}+1)^{9}9(2x)$

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