009B Sample Midterm 1, Problem 3

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Evaluate the indefinite and definite integrals.

a)
b)


Foundations:  
Integration by parts tells us that
How would you integrate
You could use integration by parts.
Let and Then, and
Thus,

Solution:

(a)

Step 1:  
We proceed using integration by parts. Let and . Then, and .
Therefore, we have
   .
Step 2:  
Now, we need to use integration by parts again. Let and . Then, and .
Building on the previous step, we have
   .

(b)

Step 1:  
We proceed using integration by parts. Let and . Then, and .
Therefore, we have
   .
Step 2:  
Now, we evaluate to get
   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{e} x^3\ln x~dx=\bigg((\ln e) \frac{e^4}{4}-\frac{e^4}{16}\bigg)-\bigg((\ln 1) \frac{1^4}{4}-\frac{1^4}{16}\bigg)=\frac{e^4}{4}-\frac{e^4}{16}+\frac{1}{16}=\frac{3e^4+1}{16}} .
Final Answer:  
(a)   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x^2e^x-2xe^x+2e^x+C}
(b)   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{3e^4+1}{16}}

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