A curve is defined implicitly by the equation
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x^{3}+y^{3}=6xy.}
a) Using implicit differentiation, compute
.
b) Find an equation of the tangent line to the curve Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x^{3}+y^{3}=6xy}
at the point
.
| Foundations:
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1. What is the result of implicit differentiation of
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- It would be
by the Product Rule.
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| 2. What two pieces of information do you need to write the equation of a line?
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- You need the slope of the line and a point on the line.
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| 3. What is the slope of the tangent line of a curve?
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- The slope is

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Solution:
(a)
| Step 1:
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Using implicit differentiation on the equation we get
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| Step 2:
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Now, we move all the terms to one side of the equation.
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| So, we have
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We solve to get
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(b)
| Step 1:
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First, we find the slope of the tangent line at the point
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We plug into the formula for we found in part (a).
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| So, we get
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| Step 2:
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Now, we have the slope of the tangent line at and a point.
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| Thus, we can write the equation of the line.
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So, the equation of the tangent line at is
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| Final Answer:
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| (a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dy}{dx}=\frac{3x^2-6y}{6x-3y^2}}
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| (b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=-1(x-3)+3}
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