Difference between revisions of "005 Sample Final A, Question 8"
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(Created page with "''' Question ''' Solve the following equation, <math> 3^{2x} + 3^x -2 = 0 </math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;"...") |
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| We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides. | | We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides. | ||
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| − | |This gives<math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math> | + | |This gives <math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math> |
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Latest revision as of 09:51, 2 June 2015
Question Solve the following equation,
| Foundations |
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| 1) What substitution can we make to simplify the problem? |
| Answer: |
| 1) Substitute to change the original equation into |
| Step 1: |
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| Start by rewriting and make the substitution |
| Step 2: |
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| After substitution we get |
| Step 3: |
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| Now we have to find the zeros of and . We do this by first isolating in both equations. |
| So and |
| Step 4: |
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| We observe that has no solutions. We can solve by taking of both sides. |
| This gives |
| Final Answer: |
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| x = 0 |