Difference between revisions of "022 Exam 2 Sample B, Problem 6"

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::<math>\int_0^{\,2} 6x^2 + 2x \,dx.</math>
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::<math>\int_0^{2} 6x^2 + 2x \,dx.</math>
 
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!Step 3: &nbsp;
 
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|FInally, we need to evaluate:
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Revision as of 16:26, 17 May 2015

Find the area under the curve of  between the -axis and .

Foundations:  
For solving the problem, we only require the use of the power rule for integration:
For setup of the problem we need to integrate the region between the x - axis, the curve, (the y-axis), and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x = 2} .

 Solution:

Step 1:  
Set up the integral:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int_0^{2} 6x^2 + 2x \,dx.}
Step 2:  
Using the power rule we have:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int _0^2 6x^2+2x \,dx \,=\, 6\cdot \frac{x^3}{3}+2\cdot \frac{x^2}{2} \Bigr|_{x\,=\,0}^2\,=\,2x^3+x^2 \Bigr|_{x\,=\,0}^2. }
Step 3:  
Finally, we need to evaluate:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2x^3 + x^2 \Bigr|_{x\,=\,0}^2 = (2(2)^3+(2)^2)-(0+0) = 20.}
Final Answer:  
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int_0^{\,2} 6x^2 + 2x \,dx\,=\,20.}

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