Difference between revisions of "022 Exam 1 Sample A, Problem 7"
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(Created page with "<span class="exam">Find the slope of the tangent line to the graph of <math style="vertical-align: -14%">f(x)=x^{3}-3x^{2}-5x+7</math> at the point <math style="vertical-align...") |
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! Foundations: | ! Foundations: | ||
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| − | |Recall that for a given value, <math style="vertical-align: - | + | |Recall that for a given value, <math style="vertical-align: -18%">f'(x)</math> is precisely the point of the tangent line through the point <math style="vertical-align: -16%">\left(x,f(x)\right)</math>. Once we have the slope, we can then use the point-slope form for a line: |
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!Write the Equation of the Line: | !Write the Equation of the Line: | ||
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| − | |Using the point-slope form listed in foundations, along with the point <math style="vertical-align: -20%">(3,-8)</math> and the slope <math style="vertical-align: | + | |Using the point-slope form listed in foundations, along with the point <math style="vertical-align: -20%">(3,-8)</math> and the slope <math style="vertical-align: -3%">m=4</math>, we find |
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Latest revision as of 19:26, 13 April 2015
Find the slope of the tangent line to the graph of at the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (3,-8)} .
| Foundations: |
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| Recall that for a given value, Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x)} is precisely the point of the tangent line through the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(x,f(x)\right)} . Once we have the slope, we can then use the point-slope form for a line: |
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| where Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m} is the known slope and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(x_0,y_0\right)} is a point on the line. |
Solution:
| Finding the slope: |
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| Note that |
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| so the tangent line through Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (3,-8)} has slope |
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| Write the Equation of the Line: |
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| Using the point-slope form listed in foundations, along with the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (3,-8)} and the slope Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m=4} , we find |
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| or |
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| Final Answer: |
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