Difference between revisions of "Math 22 Asymptotes"

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|Therefore, <math>\lim_{x\to 3^-}\frac{-2}{x-3}=\frac{\text{negative}}{\text{negative}}=\infty</math>  
 
|Therefore, <math>\lim_{x\to 3^-}\frac{-2}{x-3}=\frac{\text{negative}}{\text{negative}}=\infty</math>  
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'''2)''' <math>\lim_{x\to 2^+}\frac{-5}{x-2}</math>
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!Solution: &nbsp;
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|Notice <math>x\to 2^+</math>, so <math> x>2 </math>, then <math> x-2>0</math>, hence the denominator will be "positive".
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|Therefore, <math>\lim_{x\to 2^+}\frac{-5}{x-2}=\frac{\text{negative}}{\text{positive}}=-\infty</math>
 
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This page is under construction
 
This page is under construction

Revision as of 06:56, 4 August 2020

Vertical Asymptotes and Infinite Limits

 If  approaches infinity (or negative infinity) as  approaches  from the right or from the left, then the line

Example: Find the limit below:

1)

Solution:  
Important: is either or
Notice , so , then , hence the denominator will be "negative".
Therefore,

2)

Solution:  
Notice , so , then , hence the denominator will be "positive".
Therefore,

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