Difference between revisions of "009B Sample Midterm 2, Problem 1"
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!Final Answer: | !Final Answer: | ||
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| − | |'''(a)''' The left-endpoint Riemann sum is <math style="vertical-align: -20px">\frac{205}{144}</math>, which overestimates the area of <math style="vertical-align: 0px">S</math>. | + | | '''(a)''' The left-endpoint Riemann sum is <math style="vertical-align: -20px">\frac{205}{144}</math>, which overestimates the area of <math style="vertical-align: 0px">S</math>. |
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| − | |'''(b)''' Using left-endpoint Riemann sums: | + | | '''(b)''' Using left-endpoint Riemann sums: |
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Revision as of 15:06, 18 April 2016
Consider the region bounded by Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x=1,x=5,y={\frac {1}{x^{2}}}} and the -axis.
- a) Use four rectangles and a Riemann sum to approximate the area of the region . Sketch the region and the rectangles and
- indicate whether your rectangles overestimate or underestimate the area of .
- b) Find an expression for the area of the region as a limit. Do not evaluate the limit.
| Foundations: |
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| Recall: |
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Solution:
(a)
| Step 1: |
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| Let Since our interval is Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle [1,5]} and we are using rectangles, each rectangle has width Since the problem doesn't specify, we can choose either right- or left-endpoints. Choosing left-endpoints, the Riemann sum is |
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| Step 2: |
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| Thus, the left-endpoint Riemann sum is |
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| The left-endpoint Riemann sum overestimates the area of Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle S.} |
(b)
| Step 1: |
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| Let be the number of rectangles used in the left-endpoint Riemann sum for |
| The width of each rectangle is |
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| Step 2: |
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| So, the left-endpoint Riemann sum is |
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| Now, we let go to infinity to get a limit. |
| So, the area of is equal to |
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| Final Answer: |
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| (a) The left-endpoint Riemann sum is Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {205}{144}}} , which overestimates the area of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle S} . |
| (b) Using left-endpoint Riemann sums: |
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