Difference between revisions of "009A Sample Final 1, Problem 4"
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(Created page with "<span class="exam"> If ::::::<math>y=x^2+\cos (\pi(x^2+1))</math> <span class="exam">compute <math style="vertical-align: -12px">\frac{dy}{dx}</math> and fin...") |
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|To get a point on the line, we plug in <math style="vertical-align: -3px">x_0=1</math>  into the equation given. | |To get a point on the line, we plug in <math style="vertical-align: -3px">x_0=1</math>  into the equation given. | ||
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| − | |So, we have | + | |So, we have |
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| − | |Thus, the equation of the tangent line is | + | | |
| + | ::<math style="vertical-align: -5px">y=1^2+\cos(2\pi)=2.</math> | ||
| + | |- | ||
| + | |Thus, the equation of the tangent line is | ||
| + | |- | ||
| + | | | ||
| + | ::<math style="vertical-align: -5px">y=2(x-1)+2.</math> | ||
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Revision as of 11:06, 18 April 2016
If
compute and find the equation for the tangent line at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x_0=1} . You may leave your answers in point-slope form.
| Foundations: |
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| 1. What two pieces of information do you need to write the equation of a line? |
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| 2. What does the Chain Rule state? |
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Solution:
| Step 1: |
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| First, we compute Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dy}{dx}.} We get |
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| Step 2: |
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| To find the equation of the tangent line, we first find the slope of the line. |
| Using Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x_0=1} in the formula for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dy}{dx}} from Step 1, we get |
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| To get a point on the line, we plug in Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x_0=1} into the equation given. |
| So, we have |
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| Thus, the equation of the tangent line is |
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| Final Answer: |
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