Difference between revisions of "008A Sample Final A, Question 17"

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! Final Answer C:
 
! Final Answer C:
 
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|Sin(-120) = - sin(120). So you can either compute sin(120) or sin(-120) = sin(240). Since the reference angle is 60 degrees, or <math>\frac{\pi}{3}</math>, So <math> sin(-120) = \frac{\sqrt{3}}{2}</math>
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|Sin(-120) = - sin(120). So you can either compute sin(120) or sin(-120) = sin(240). Since the reference angle is 60 degrees, or <math>\frac{\pi}{3}</math>&nbsp;, So &nbsp;<math> \sin(-120) = \frac{\sqrt{3}}{2}</math>
 
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[[008A Sample Final A|<u>'''Return to Sample Exam</u>''']]
 
[[008A Sample Final A|<u>'''Return to Sample Exam</u>''']]

Revision as of 16:15, 23 May 2015

Question: Compute the following trig ratios: a)       b)       c)

Foundations
1) How is secant related to either sine or cosine?
2) What quadrant is each angle in? What is the reference angle for each? Answer:
1) Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \sec(x)={\frac {1}{\cos(x)}}}
2) a) Quadrant 2, b) Quadrant 4, c) Quadrant 3. The reference angles are: Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {\pi }{4}},{\frac {\pi }{6}}} , and 60 degrees or

Solution:

Final Answer A:
Since Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \sec(x)={\frac {1}{\cos(x)}}} , and the angle is in quadrant 2, Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \sec({\frac {3\pi }{4}})={\frac {1}{\cos({\frac {3\pi }{4}})}}={\frac {1}{\frac {-1}{\sqrt {2}}}}=-{\sqrt {2}}}
Final Answer B:
The reference angle is and is in the fourth quadrant. So tangent will be negative. Since the angle is 30 degees, using the 30-60-90 right triangle, we can conclude that Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \tan({\frac {11\pi }{6}})=-{\frac {\sqrt {3}}{3}}}
Final Answer C:
Sin(-120) = - sin(120). So you can either compute sin(120) or sin(-120) = sin(240). Since the reference angle is 60 degrees, or  , So  Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sin(-120) = \frac{\sqrt{3}}{2}}

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