Difference between revisions of "Math 22 Higher-Order Derivative"
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!Solution: | !Solution: | ||
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− | |f'(x)=4x^3+15x^2-4x | + | |<math>f'(x)=4x^3+15x^2-4x</math> |
|- | |- | ||
− | |f''(x)=12x^2+30x-4 | + | |<math>f''(x)=12x^2+30x-4</math> |
|- | |- | ||
− | |f'''(x)=24x+30 | + | |<math>f'''(x)=24x+30</math> |
|- | |- | ||
− | |f^{(4)}(x)=24 | + | |<math>f^{(4)}(x)=24</math> |
|} | |} | ||
Revision as of 08:36, 25 July 2020
Higher-Order Derivatives
The "standard" derivative is called the first derivative of . The derivative of is the second derivative of, denoted by By continuing this process, we obtain higher-order derivative of .
Note: The 3rd derivative of is . However, we simply denote the derivative as for
Example: Find the first four derivative of
1)
Solution: |
---|
2)
Solution: |
---|
It is better to rewrite |
Then, |
Notes
If is the position function, then is the velocity function and is the acceleration function.
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