Difference between revisions of "Math 22 Limits"
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'''1. Direct Substitution''': Direct Substitution can be used to find the limit of a Polynomial Function. | '''1. Direct Substitution''': Direct Substitution can be used to find the limit of a Polynomial Function. | ||
− | Example: Evaluate <math>lim_{x\to 3} x^2+2x-1=(3)^2+2(3)-1=14</math> | + | Example: Evaluate <math>\lim_{x\to 3} x^2+2x-1=(3)^2+2(3)-1=14</math> |
'''2. Dividing Out Technique''': When direct substitution fails and numerator or/and denominator can be factored. | '''2. Dividing Out Technique''': When direct substitution fails and numerator or/and denominator can be factored. | ||
− | Example: Evaluate <math>lim_{x\to 2} \frac {x^2-4}{x^2-x-2}= lim_{x\to 2} \frac {(x-2)(x+2)}{(x-2)(x+1)}=lim_{x\to 2} \frac {x+2}{x+1}</math>. Now we can use direct substitution to get the answer. | + | Example: Evaluate <math>\lim_{x\to 2} \frac {x^2-4}{x^2-x-2}= \lim_{x\to 2} \frac {(x-2)(x+2)}{(x-2)(x+1)}=\lim_{x\to 2} \frac {x+2}{x+1}</math>. Now we can use direct substitution to get the answer. |
'''3. Rationalizing (Using Conjugate)''': When direct substitution fails and either numerator or denominator has a square root. In this case, we can try to multiply both numerator and denominator by the conjugate. | '''3. Rationalizing (Using Conjugate)''': When direct substitution fails and either numerator or denominator has a square root. In this case, we can try to multiply both numerator and denominator by the conjugate. | ||
− | Example: Evaluate <math>lim_{x\to 0} \frac {\sqrt{x+4}-2}{x}= lim_{x\to 0} \frac {\sqrt{x+4}-2} {x} \cdot \frac {\sqrt{x+4}+2}{\sqrt{x+4}+2}= lim_{x\to 0} \frac {(x+4)-4}{x(\sqrt{x+4}+2)}=lim_{x\to 0} \frac {x}{x(\sqrt{x+4}+2)}=lim_{x\to 0} \frac {1}{\sqrt{x+4}+2}</math>. Now we can use direct substitution to get the answer | + | Example: Evaluate <math>\lim_{x\to 0} \frac {\sqrt{x+4}-2}{x}= \lim_{x\to 0} \frac {\sqrt{x+4}-2} {x} \cdot \frac {\sqrt{x+4}+2}{\sqrt{x+4}+2}= \lim_{x\to 0} \frac {(x+4)-4}{x(\sqrt{x+4}+2)}=\lim_{x\to 0} \frac {x}{x(\sqrt{x+4}+2)}=\lim_{x\to 0} \frac {1}{\sqrt{x+4}+2}</math>. Now we can use direct substitution to get the answer |
==One-Sided Limits and Unbounded Function== | ==One-Sided Limits and Unbounded Function== |
Revision as of 06:40, 14 July 2020
The Limit of a Function
Definition of the Limit of a Function If becomes arbitrarily close to a single number as approaches from either side, then which is read as "the limit of as approaches is
Note: Many times the limit of as approaches is simply , so limit can be evaluate by direct substitution as
Properties of Limits
Let and be real numbers, let be a positive integer, and let and be functions with the following limits and . Then
1. Scalar multiple:
2. Sum or difference:
3. Product:
4. Quotient:
5. Power:
6. Radical:
Techniques for Evaluating Limits
1. Direct Substitution: Direct Substitution can be used to find the limit of a Polynomial Function.
Example: Evaluate
2. Dividing Out Technique: When direct substitution fails and numerator or/and denominator can be factored.
Example: Evaluate . Now we can use direct substitution to get the answer.
3. Rationalizing (Using Conjugate): When direct substitution fails and either numerator or denominator has a square root. In this case, we can try to multiply both numerator and denominator by the conjugate.
Example: Evaluate . Now we can use direct substitution to get the answer
One-Sided Limits and Unbounded Function
when a function approaches a different value from the left of than it approaches from the right of , the limit does not exists. However, this type of behavior can be described more concisely with the concept of a one-sided limit. We denote and
One-sided Limit is related to unbounded function.
Consider
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This page were made by Tri Phan