Difference between revisions of "022 Sample Final A, Problem 8"
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::<math>\begin{array}{rcl} | ::<math>\begin{array}{rcl} | ||
− | \frac{\partial f}{\partial l}(k,l) & = & {\displaystyle 200k^{0.6}\left(0.4l^{\,0.4-1}\right)}\\ | + | \displaystyle{\frac{\partial f}{\partial l}}(k,l) & = & {\displaystyle 200k^{0.6}\left(0.4l^{\,0.4-1}\right)}\\ |
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& = & 200k^{0.6}\left(\frac{2}{5}l^{-0.6}\right)\\ | & = & 200k^{0.6}\left(\frac{2}{5}l^{-0.6}\right)\\ | ||
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::<math>\begin{array}{rcl} | ::<math>\begin{array}{rcl} | ||
− | \frac{\partial f}{\partial k}(k,l) & = & {\displaystyle 200\left(0.6k^{0.6-1}\right)l^{0.4}}\\ | + | \displaystyle{\frac{\partial f}{\partial k}}(k,l) & = & {\displaystyle 200\left(0.6k^{0.6-1}\right)l^{0.4}}\\ |
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& = & 200\left(\frac{3}{5}k^{-0.4}\right) l^{\,0.4}\\ | & = & 200\left(\frac{3}{5}k^{-0.4}\right) l^{\,0.4}\\ |
Latest revision as of 17:09, 6 June 2015
Find ther marginal productivity of labor and marginal productivity of capital for the following Cobb-Douglas production function:
(Note: You must simplify so your solution does not contain negative exponents.)
Foundations: |
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The word 'marginal' should make you immediately think of a derivative. In this case, the marginal is just the partial derivative with respect to a particular variable. |
The teacher has also added the additional restriction that you should not leave your answer with negative exponents. |
Solution:
Marginal productivity of labor: |
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We take the partial derivative with respect to : |
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Marginal productivity of capital: |
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Now, we take the partial derivative with respect to : |
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Final Answer: |
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Marginal productivity of labor:
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Marginal productivity of capital:
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