Difference between revisions of "022 Exam 2 Sample B, Problem 9"
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(Created page with "<span class="exam"> Find all relative extrema and points of inflection for the function <math style="vertical-align: -16%">g(x) = x^3 - 3x</math>. Be sure to give coordinate p...") |
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| − | |'''Test the potential extrema:''' We know that <math style="vertical-align: | + | |'''Test the potential extrema:''' We know that <math style="vertical-align: -2%">x=\pm1</math> are the candidates. We check the second derivative, finding |
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| − | |'''Test the potential inflection point:''' We know that <math style="vertical-align: -25%">g\,''(0)=0</math>. On the other hand, it should be clear that if <math style="vertical-align: 0%">x<0</math>, then <math style="vertical-align: -20%">g\,''(x)<0</math>. Similarly, if <math style="vertical-align: -20%">x>0,</math> then <math style="vertical-align: -20%">g\,''(x)>0</math>. Thus, the second derivative "splits" around <math style="vertical-align: | + | |'''Test the potential inflection point:''' We know that <math style="vertical-align: -25%">g\,''(0)=0</math>. On the other hand, it should be clear that if <math style="vertical-align: 0%">x<0</math>, then <math style="vertical-align: -20%">g\,''(x)<0</math>. Similarly, if <math style="vertical-align: -20%">x>0,</math> then <math style="vertical-align: -20%">g\,''(x)>0</math>. Thus, the second derivative "splits" around <math style="vertical-align: -3%">x=0</math>  (i.e., changes sign), so the point <math style="vertical-align: -25%">\left(0,g(0)\right)=(0,0)</math>  is an inflection point. |
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Latest revision as of 17:34, 17 May 2015
Find all relative extrema and points of inflection for the function . Be sure to give coordinate pairs for each point. You do not need to draw the graph. Explain how you know which point is the local minimum and which is the local maximum (i.e., which test did you use?).
| Foundations: |
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| Since our function is a polynomial, the relative extrema occur when the first derivative is zero. We then have two choices for finding if it is a local maximum or minimum: |
| Second Derivative Test: If the first derivative at a point is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0} , and the second derivative is negative (indicating it is concave-down, like an upside-down parabola), then the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(x_0,f(x_0)\right)} is a local maximum. |
| On the other hand, if the second derivative is positive, the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(x_0,f(x_0)\right)} is a local minimum. You can also use the first derivative test, but it is usually a bit more work! For inflection points, we need to find when the second derivative is zero, as well as check that the second derivative "splits" on both sides. |
Solution:
| Step 1: |
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| Find the first and second derivatives: Based on our function, we have |
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| Similarly, from the first derivative we find |
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| Step 2: |
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| Find the roots of the derivatives: We can rewrite the first derivative as |
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| from which it should be clear we have roots Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \pm1} . |
| On the other hand, for the second derivative, we have only a single root: Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=0} . |
| Step 3: |
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| Test the potential extrema: We know that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=\pm1} are the candidates. We check the second derivative, finding |
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| while |
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| Note that |
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| while |
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| By the second derivative test, the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (1,g(1))=\left(1,-2\right)} is a relative minimum, while the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (-1,g(-1))=(-1,2)} is a relative maximum. |
| Step 4: |
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| Test the potential inflection point: We know that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g\,''(0)=0} . On the other hand, it should be clear that if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x<0} , then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g\,''(x)<0} . Similarly, if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x>0,} then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle g\,''(x)>0} . Thus, the second derivative "splits" around Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=0} (i.e., changes sign), so the point Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(0,g(0)\right)=(0,0)} is an inflection point. |
| Final Answer: |
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| There is a local minimum at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (1,-2)} , a local maximum at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (-1,2)} and an inflection point at Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (0,0).} |