Difference between revisions of "Math 22 Extrema of Functions of Two Variables"
Jump to navigation
Jump to search
(Created page with " '''Return to Topics Page''' '''This page were made by Tri Phan'''") |
|||
| (3 intermediate revisions by the same user not shown) | |||
| Line 1: | Line 1: | ||
| + | ==Relative Extrema of a Function of Two Variables== | ||
| + | Let <math>f</math> be a function defined on a region containing <math>(x_0,y_0)</math>. The function <math>f</math> has a relative maximum at <math>(x_0,y_0)</math> when there is a circular region centered at <math>(x_0,y_0)</math> such that | ||
| + | |||
| + | <math>f(x,y)\le f(x_0,y_0)</math> | ||
| + | |||
| + | for all <math>(x,y)</math> in <math>R</math>. | ||
| + | The function <math>f</math> has a relative minimum at <math>(x_0,y_0)</math> when there is a circular region centered at <math>(x_0,y_0)</math> such that | ||
| + | |||
| + | <math>f(x,y)\ge f(x_0,y_0)</math> | ||
| + | |||
| + | for all <math>(x,y)</math> in <math>R</math>. | ||
| + | ==First-Partials Test for Relative Extrema== | ||
| + | If <math>f</math> has a relative extremum at on an open region <math>R</math> in the xy-plane, and the first partial derivatives of <math>f</math> exist in <math>R</math>, then | ||
| + | |||
| + | <math>f_x(x_0,y_0)=0</math> and <math>f_y(x_0,y_0)=0</math> | ||
| + | '''Example:''' Find the relative critical point of of: | ||
| + | '''1)''' <math>f(x,y)=2x^2+y^2+8x-6y+20</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |Consider: <math>f_x(x,y)=4x+8=0</math>, so <math>x=-2</math> | ||
| + | |- | ||
| + | |and: <math>f_y(x,y)=2y-6=0</math>, so <math>y=3</math> | ||
| + | |- | ||
| + | |Therefore, there is a critical point at <math>(-2,3)</math> | ||
| + | |} | ||
| + | ==The Second-Partials Test for Relative Extrema== | ||
| + | Let <math>f</math> have continuous second partial derivatives on an open region containing <math>(a,b)</math> for which <math>f_x(a,b)=0</math> and <math>f_y(a,b)=0</math> | ||
| + | Then, consider <math>d=f_{xx}(a,b)f_{yy}(a,b)-[f_{xy}(a,b)]^2</math> | ||
| + | |||
| + | Then: | ||
| + | 1. If <math>d>0</math> and <math>f_{xx}(a,b)>0</math>, then <math>f</math> has a relative minimum at <math>(a,b)</math>. | ||
| + | 2. If <math>d>0</math> and <math>f_{xx}(a,b)<0</math>, then <math>f</math> has a relative maximum at <math>(a,b)</math>. | ||
| + | 3. If <math>d<0</math>, then <math>(a,b,f(a,b))</math> is a saddle point. | ||
| + | 4. If <math>d=0</math>, no conclusion. | ||
| + | '''Example:''' Find the relative extrema (maximum or minimum): | ||
| − | + | '''1)''' <math>f(x,y)=2x^2+y^2+8x-6y+20</math> | |
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |Consider: <math>f_x(x,y)=4x+8=0</math>, so <math>x=-2</math> | ||
| + | |- | ||
| + | |and: <math>f_y(x,y)=2y-6=0</math>, so <math>y=3</math> | ||
| + | |- | ||
| + | |Therefore, there is a critical point at <math>(-2,3)</math> | ||
| + | |- | ||
| + | |Now: <math>f_{xx}f(x,y)=4</math> | ||
| + | |- | ||
| + | |<math>f_{yy}f(x,y)=2</math> | ||
| + | |- | ||
| + | |and <math>f_{xy}f(x,y)=0</math> | ||
| + | |- | ||
| + | |Then, <math>d=f_{xx}(a,b)f_{yy}(a,b)-[f_{xy}(a,b)]^2=(4)(2)-0^2=8</math> | ||
| + | |- | ||
| + | |Since, <math>d>0</math> and <math>f_{xx}f(x,y)=4>0</math>, then by the second-partial test, <math>f</math> has a relative minumum at <math>(-2,3)</math> | ||
| + | |} | ||
[[Math_22| '''Return to Topics Page''']] | [[Math_22| '''Return to Topics Page''']] | ||
'''This page were made by [[Contributors|Tri Phan]]''' | '''This page were made by [[Contributors|Tri Phan]]''' | ||
Latest revision as of 08:32, 18 August 2020
Relative Extrema of a Function of Two Variables
Let be a function defined on a region containing . The function has a relative maximum at when there is a circular region centered at such that for all in .
The function has a relative minimum at when there is a circular region centered at such that for all in .
First-Partials Test for Relative Extrema
If has a relative extremum at on an open region in the xy-plane, and the first partial derivatives of exist in , then and
Example: Find the relative critical point of of:
1)
| Solution: |
|---|
| Consider: , so |
| and: , so |
| Therefore, there is a critical point at |
The Second-Partials Test for Relative Extrema
Let have continuous second partial derivatives on an open region containing for which and Then, consider Then: 1. If and , then has a relative minimum at . 2. If and , then has a relative maximum at . 3. If , then is a saddle point. 4. If , no conclusion.
Example: Find the relative extrema (maximum or minimum):
1)
| Solution: |
|---|
| Consider: , so |
| and: , so |
| Therefore, there is a critical point at |
| Now: |
| and |
| Then, |
| Since, and , then by the second-partial test, has a relative minumum at |
This page were made by Tri Phan