Difference between revisions of "Math 22 Logarithmic Functions"

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   5.<math>\ln{x^n}=n\ln x</math>
 
   5.<math>\ln{x^n}=n\ln x</math>
  
'''Exercises''' Use the properties of logarithms to rewrite the expression as the logarithm of a single quantity  
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'''Exercises 1''' Use the properties of logarithms to rewrite the expression as the logarithm of a single quantity  
  
 
'''a)''' <math>\ln(x-2)-\ln(x+2)</math>
 
'''a)''' <math>\ln(x-2)-\ln(x+2)</math>
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!Solution: &nbsp;
 
!Solution: &nbsp;
 
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|-
|<math>f'(x)=6xe^{3x^2}</math>
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|<math>7\ln (5x+4)-\frac{3}{2}\ln (x-9)=\ln (5x+4)^7-\ln (x-9)^{\frac{3}{2}}=\ln\frac{(5x+4)^7}{(x-9)^{\frac{3}{2}}}</math>
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|}
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'''Exercises 2''' Solve for x.
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'''a)''' <math>\ln(2x)=5</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|<math>\ln(2x)=5</math>, so <math>e^5=2x</math>, hence <math>x=\frac{e^5}{2}</math>
 
|}
 
|}
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'''b)''' <math>5\ln x=3</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|<math>5\ln x=3</math>, so <math>ln {x^5}=3</math>, so <math>e^3=x^5</math>, hence <math>x=\sqrt[5]{e^3}</math>
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|}
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[[Math_22| '''Return to Topics Page''']]
 
[[Math_22| '''Return to Topics Page''']]
  
 
'''This page were made by [[Contributors|Tri Phan]]'''
 
'''This page were made by [[Contributors|Tri Phan]]'''

Latest revision as of 08:44, 11 August 2020

Logarithm Function

 The logarithm  is defined as 
  if and only if 

Definition of the Natural Logarithmic Function

 The natural logarithmic function, denoted by , is defined as
  if and only if 

Properties of the Natural Logarithmic Function

 Let 
 1. The domain of  is  and the range of  is 
 2. The x-intercept of the graph of  is 
 3. The function  is continuous, increasing, and one-to-one.
 4.  and 

Inverse Properties of Logarithms and Exponents

 1.
 
 2.
 
 3.
 
 4.
 
 5.


Exercises 1 Use the properties of logarithms to rewrite the expression as the logarithm of a single quantity

a)

Solution:  

b)

Solution:  

c)

Solution:  

d)

Solution:  

Exercises 2 Solve for x.

a)

Solution:  
, so , hence

b)

Solution:  
, so , so , hence


Return to Topics Page

This page were made by Tri Phan