Difference between revisions of "Math 22 Natural Exponential Functions"
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Let <math>P</math> be the amount deposited, <math>t</math> the number of years, <math>A</math> the balance, | Let <math>P</math> be the amount deposited, <math>t</math> the number of years, <math>A</math> the balance, | ||
and <math>r</math> the annual interest rate (in decimal form). | and <math>r</math> the annual interest rate (in decimal form). | ||
− | 1. Compounded <math>n</math> times per year: <math>A=P(1+\frac{r}{n})^{ | + | 1. Compounded <math>n</math> times per year: <math>A=P(1+\frac{r}{n})^{nt}</math> |
2. Compounded continuously: <math>A=Pe^{rt}</math> | 2. Compounded continuously: <math>A=Pe^{rt}</math> | ||
− | '''Exercises''' Find the balance in an account when | + | '''Exercises''' Find the balance in an account when $3000 is deposited for 10 years at an interest rate of 4%, compounded as follows. |
− | '''a)''' | + | '''a)''' Quarterly |
{| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
!Solution: | !Solution: | ||
|- | |- | ||
− | |<math>( | + | |<math>A=3000(1+\frac{0.04}{4})^{(4)10}</math> |
|} | |} | ||
+ | '''a)''' Annually | ||
+ | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | !Solution: | ||
+ | |- | ||
+ | |<math>A=3000(1+\frac{0.04}{1})^{(1)10}</math> | ||
+ | |} | ||
+ | |||
+ | '''a)''' Monthly | ||
+ | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | !Solution: | ||
+ | |- | ||
+ | |<math>A=3000(1+\frac{0.04}{12})^{(12)10}</math> | ||
+ | |} | ||
+ | '''a)''' Daily | ||
+ | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | !Solution: | ||
+ | |- | ||
+ | |<math>A=3000(1+\frac{0.04}{365})^{(365)10}</math> | ||
+ | |} | ||
+ | |||
+ | '''a)''' Continuously | ||
+ | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | !Solution: | ||
+ | |- | ||
+ | |<math>A=Pe^{rt}=3000(e^{(0.04) (10)})</math> | ||
+ | |} | ||
+ | |||
+ | ==Present Value== | ||
+ | |||
+ | <math>P=\frac{A}{(1+\frac{r}{n})^{n t}}</math> | ||
+ | |||
+ | '''Exercises''' How much money should be deposited in an account paying 5% interest compounded monthly in order to have a balance of $20000 after 5 years? | ||
+ | |||
+ | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
+ | !Solution: | ||
+ | |- | ||
+ | |This is present value problem. So | ||
+ | |- | ||
+ | |<math>P=\frac{A}{(1+\frac{r}{n})^{n t}}=\frac{20000}{(1+\frac{0.05}{12})^{(12)(5)}}</math> | ||
+ | |} | ||
[[Math_22| '''Return to Topics Page''']] | [[Math_22| '''Return to Topics Page''']] | ||
'''This page were made by [[Contributors|Tri Phan]]''' | '''This page were made by [[Contributors|Tri Phan]]''' |
Latest revision as of 07:12, 11 August 2020
Limit Definition of
The irrational number is defined to be the limit:
Compound Interest
Let be the amount deposited, the number of years, the balance, and the annual interest rate (in decimal form). 1. Compounded times per year: 2. Compounded continuously:
Exercises Find the balance in an account when $3000 is deposited for 10 years at an interest rate of 4%, compounded as follows.
a) Quarterly
Solution: |
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a) Annually
Solution: |
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a) Monthly
Solution: |
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a) Daily
Solution: |
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a) Continuously
Solution: |
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Present Value
Exercises How much money should be deposited in an account paying 5% interest compounded monthly in order to have a balance of $20000 after 5 years?
Solution: |
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This is present value problem. So |
This page were made by Tri Phan