Difference between revisions of "Math 22 Natural Exponential Functions"
Jump to navigation
Jump to search
| (9 intermediate revisions by the same user not shown) | |||
| Line 3: | Line 3: | ||
<math>\lim_{x\to 0} (1+x)^{\frac{1}{x}}=e</math> | <math>\lim_{x\to 0} (1+x)^{\frac{1}{x}}=e</math> | ||
<math>e\approx 2.71828182846</math> | <math>e\approx 2.71828182846</math> | ||
| + | |||
| + | ==Compound Interest== | ||
| + | Let <math>P</math> be the amount deposited, <math>t</math> the number of years, <math>A</math> the balance, | ||
| + | and <math>r</math> the annual interest rate (in decimal form). | ||
| + | 1. Compounded <math>n</math> times per year: <math>A=P(1+\frac{r}{n})^{nt}</math> | ||
| + | 2. Compounded continuously: <math>A=Pe^{rt}</math> | ||
| + | |||
| + | '''Exercises''' Find the balance in an account when $3000 is deposited for 10 years at an interest rate of 4%, compounded as follows. | ||
| + | |||
| + | '''a)''' Quarterly | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>A=3000(1+\frac{0.04}{4})^{(4)10}</math> | ||
| + | |} | ||
| + | |||
| + | '''a)''' Annually | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>A=3000(1+\frac{0.04}{1})^{(1)10}</math> | ||
| + | |} | ||
| + | |||
| + | '''a)''' Monthly | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>A=3000(1+\frac{0.04}{12})^{(12)10}</math> | ||
| + | |} | ||
| + | |||
| + | '''a)''' Daily | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>A=3000(1+\frac{0.04}{365})^{(365)10}</math> | ||
| + | |} | ||
| + | |||
| + | '''a)''' Continuously | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>A=Pe^{rt}=3000(e^{(0.04) (10)})</math> | ||
| + | |} | ||
| + | |||
| + | ==Present Value== | ||
| + | |||
| + | <math>P=\frac{A}{(1+\frac{r}{n})^{n t}}</math> | ||
| + | |||
| + | '''Exercises''' How much money should be deposited in an account paying 5% interest compounded monthly in order to have a balance of $20000 after 5 years? | ||
| + | |||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |This is present value problem. So | ||
| + | |- | ||
| + | |<math>P=\frac{A}{(1+\frac{r}{n})^{n t}}=\frac{20000}{(1+\frac{0.05}{12})^{(12)(5)}}</math> | ||
| + | |} | ||
| + | |||
[[Math_22| '''Return to Topics Page''']] | [[Math_22| '''Return to Topics Page''']] | ||
'''This page were made by [[Contributors|Tri Phan]]''' | '''This page were made by [[Contributors|Tri Phan]]''' | ||
Latest revision as of 07:12, 11 August 2020
Limit Definition of
The irrational number is defined to be the limit:
Compound Interest
Let be the amount deposited, the number of years, the balance, and the annual interest rate (in decimal form). 1. Compounded times per year: 2. Compounded continuously:
Exercises Find the balance in an account when $3000 is deposited for 10 years at an interest rate of 4%, compounded as follows.
a) Quarterly
| Solution: |
|---|
a) Annually
| Solution: |
|---|
a) Monthly
| Solution: |
|---|
a) Daily
| Solution: |
|---|
a) Continuously
| Solution: |
|---|
Present Value
Exercises How much money should be deposited in an account paying 5% interest compounded monthly in order to have a balance of $20000 after 5 years?
| Solution: |
|---|
| This is present value problem. So |
This page were made by Tri Phan