Difference between revisions of "Math 22 Differentials and Marginal Analysis"

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!Solution:  
 
!Solution:  
 
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|Notice: <math>y=x(1.25+0.02\sqrt{x})=1.25x+0.02x\sqrt{x}=1.25x+0.02x^{\frac{3}{2}}</math>, so <math>dy=f'(x)dx=1.25dx+0.02(\frac{3}{2})x^{\frac{1}{2}}=\frac{1}{3} dx</math>
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|Notice: <math>y=x(1.25+0.02\sqrt{x})=1.25x+0.02x\sqrt{x}=1.25x+0.02x^{\frac{3}{2}}</math>, so <math>dy=f'(x)dx=[1.25+0.02(\frac{3}{2})x^{\frac{1}{2}}]dx=[1.25+0.03\sqrt{x}]dx</math>
 
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Latest revision as of 07:00, 10 August 2020

Differentials

 Let  represent a differentiable function. The differential of  (denoted by )
 is any nonzero real number. The differential of  (denoted by ) is .

Example: 1) Consider the function . Find when and

Solution:  
Notice: , so

2) Find of each function below:

a)

Solution:  
Notice: , so

b)

Solution:  
Notice: , so

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