Difference between revisions of "005 Sample Final A, Question 8"
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(Created page with "''' Question ''' Solve the following equation, <math> 3^{2x} + 3^x -2 = 0 </math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;"...") |
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| We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides. | | We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides. | ||
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− | |This gives<math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math> | + | |This gives <math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math> |
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Latest revision as of 09:51, 2 June 2015
Question Solve the following equation,
Foundations |
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1) What substitution can we make to simplify the problem? |
Answer: |
1) Substitute to change the original equation into |
Step 1: |
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Start by rewriting and make the substitution |
Step 2: |
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After substitution we get |
Step 3: |
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Now we have to find the zeros of and . We do this by first isolating in both equations. |
So and |
Step 4: |
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We observe that has no solutions. We can solve by taking of both sides. |
This gives |
Final Answer: |
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x = 0 |