Difference between revisions of "005 Sample Final A, Question 8"

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(Created page with "''' Question ''' Solve the following equation,      <math> 3^{2x} + 3^x -2 = 0 </math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;"...")
 
 
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| We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides.
 
| We observe that <math>3^x = -2</math> has no solutions. We can solve <math>3^x = 1</math> by taking <math>log_3</math> of both sides.
 
|-
 
|-
|This gives<math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math>
+
|This gives <math>\log_3\left(3^x\right) = x = \log_3(1) = 0</math>
 
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Latest revision as of 09:51, 2 June 2015

Question Solve the following equation,     


Foundations
1) What substitution can we make to simplify the problem?
Answer:
1) Substitute to change the original equation into


Step 1:
Start by rewriting and make the substitution
Step 2:
After substitution we get
Step 3:
Now we have to find the zeros of and . We do this by first isolating in both equations.
So and
Step 4:
We observe that has no solutions. We can solve by taking of both sides.
This gives
Final Answer:
x = 0

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