Difference between revisions of "004 Sample Final A, Problem 4"
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! Step 1: | ! Step 1: | ||
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− | |First we replace the inequalities with equality. So <math>y = | + | |First we replace the inequalities with equality. So <math>y = 2x - 3</math>, and <math>y = 4 - x^2</math>. |
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|Now we graph both functions. | |Now we graph both functions. | ||
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|point satisfies the inequality or not. For both equations we will pick the origin. | |point satisfies the inequality or not. For both equations we will pick the origin. | ||
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− | |<math>y | + | |<math>y > 2x - 3:</math> Plugging in the origin we get, <math> 0 > 2(0) - 3 = -3 </math>. Since the inequality is false, we shade the side of |
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− | |<math>y | + | |<math>y = 2x - 3</math> that does not include the origin. We make the graph of <math>y < \vert x\vert + 1</math> dashed, since the inequality is strict. |
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− | |<math>x^2 | + | |<math>y \le 4 - x^2:</math> Plugging in the origin we get <math>0 \le 4 - (0)^2 = 4</math>. Since this inequality is true, we shade the side of <math>y = 4 - x^2</math> that includes the origin. Here we make the graph of <math> y = 4 - x^2 </math> solid since the inequality sign is <math>\le</math> |
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! Final Answer: | ! Final Answer: | ||
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− | |The final solution is the portion of the graph that below <math>y = | + | |The final solution is the portion of the graph that below <math>y = 4 - x^2</math> and above <math> y = 2x - 3</math> |
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|The region we are referring to is shaded both blue and red. | |The region we are referring to is shaded both blue and red. | ||
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− | |[[File: | + | |[[File:4_Sample_Final_4.png]] |
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[[004 Sample Final A|<u>'''Return to Sample Exam</u>''']] | [[004 Sample Final A|<u>'''Return to Sample Exam</u>''']] |
Latest revision as of 09:08, 2 June 2015
Graph the system of inequalities. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y > 2x - 3 \qquad y \le 4-x^2} Solution:
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