Difference between revisions of "022 Exam 2 Sample A, Problem 4"

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|This problem requires three rules of integration.  In particular, you need
 
|This problem requires three rules of integration.  In particular, you need
 
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|'''Integration by substitution (U - sub):''' If <math>u = g(x)</math> is a differentiable functions whose range is in the domain of <math>f</math>, then
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|'''Integration by substitution (u - sub):''' If <math>u = g(x)</math> is a differentiable functions whose range is in the domain of <math>f</math>, then
 
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|-
 
|<math>\int g'(x)f(g(x)) dx = \int f(u) du.</math>
 
|<math>\int g'(x)f(g(x)) dx = \int f(u) du.</math>
 
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|We also need the derivative of the natural log since we will recover natural log from integration:
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|We also need our power rule for integration:
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|<math>\left(ln(x)\right)' = \frac{1}{x}</math>
 
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||Finally, we will need our power rule for integration:
 
 
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Revision as of 14:47, 15 May 2015

Find the antiderivative of

Foundations:  
This problem requires three rules of integration. In particular, you need
Integration by substitution (u - sub): If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u = g(x)} is a differentiable functions whose range is in the domain of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f} , then
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int g'(x)f(g(x)) dx = \int f(u) du.}
We also need our power rule for integration:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int x^n dx \,=\, \frac{x^{n + 1}}{n + 1},} for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n\neq 0} ,

 Solution:

Step 1:  
Use a U-substitution with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u = 3x + 2.} This means Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle du = 3 dx} , and after substitution we have
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int \left(3x + 2\right)^4 dx = \int u^4 du}
Step 2:  
We can no apply the power rule for integration:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int u^4 du = \frac{u^5}{5}}
Step 3:  
Since our original function is a function of x, we must substitute x back into the result from problem 2:
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{u^5}{5} = \frac{(3x + 2)^5}{5}}
Step 4:  
As will all indefinite integrals, don't forget the "+C" at the end.
Final Answer:  
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int \left(3x + 2\right)^5 dx\,=\, \frac{(3x + 2)^5}{5} + C}

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