Difference between revisions of "022 Exam 2 Sample A, Problem 4"
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(Created page with "<span class="exam"> Find the antiderivative of <math style="vertical-align: -45%">\int (3x+2)^4\,dx.</math> {| class="mw-collapsible mw-collapsed" style = "text-align:left;"...") |
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| − | |This problem requires | + | |This problem requires three rules of integration. In particular, you need |
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| − | | | + | |'''Integration by substitution (U - sub):''' If <math>u = g(x)</math> is a differentiable functions whose range is in the domain of <math>f</math>, then |
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| + | |<math>\int g'(x)f(g(x)) dx = \int f(u) du.</math> | ||
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| + | |We also need the derivative of the natural log since we will recover natural log from integration: | ||
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| + | |<math>\left(ln(x)\right)' = \frac{1}{x}</math> | ||
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| − | || | + | ||Finally, we will need our power rule for integration: |
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Revision as of 10:03, 15 May 2015
Find the antiderivative of
| Foundations: |
|---|
| This problem requires three rules of integration. In particular, you need |
| Integration by substitution (U - sub): If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u = g(x)} is a differentiable functions whose range is in the domain of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f} , then |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int g'(x)f(g(x)) dx = \int f(u) du.} |
| We also need the derivative of the natural log since we will recover natural log from integration: |
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left(ln(x)\right)' = \frac{1}{x}} |
| Finally, we will need our power rule for integration: |
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Solution:
| Step 1: |
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Use a U-substitution with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u = 3x + 2.}
This means Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle du = 3 dx}
, and after substitution we have
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| Step 2: |
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We can no apply the power rule for integration:
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| Step 3: |
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| Since our original function is a function of x, we must substitute x back into the result from problem 2: |
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| Step 4: |
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| As will all indefinite integrals, don't forget the "+C" at the end. |
| Final Answer: |
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| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int \left(3x + 2\right)^5 dx\,=\, \frac{(3x + 2)^5}{5} + C} |