Difference between revisions of "Math 22 The Three-Dimensional Coordinate System"

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   <math>d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}</math>
 
   <math>d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}</math>
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'''Exercises 1''' Find the distance between two points
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'''1)''' <math>(4,2,3) and <math>(1,2,0)</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|<math>d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}=\sqrt{(1-4)^2+(2-2)^2+(0-3)^2}=\sqrt{18}</math>
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|-
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|}
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'''2)''' <math>(1,2,4) and <math>(2,5,1)</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|<math>d=\sqrt{(2-1)^2+(5-2)^2+(1-4)^2}=\sqrt{19}</math>
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|-
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|}
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==Midpoint Formula in Space==
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Revision as of 06:31, 18 August 2020

The Three-Dimensional Coordinate System

3d spaces.png

The Distance and Midpoint Formulas

 The distance  between the points  and  is

Exercises 1 Find the distance between two points

1)

Solution:  

2)

Solution:  

Midpoint Formula in Space

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