Difference between revisions of "Math 22 Exponential and Logarithmic Integrals"

From Math Wiki
Jump to navigation Jump to search
Line 1: Line 1:
 
+
==Integrals of Exponential Functions==
 
+
  Let <math>u</math> be a differentiable function of <math>x</math>, then
 
+
  <math>\int e^x dx=e^x+C</math>
 
+
 
Under Construction
+
  <math>\int e^u \frac{du}{dx}dx=\int e^u du=e^u+C</math>
  
 
[[Math_22| '''Return to Topics Page''']]
 
[[Math_22| '''Return to Topics Page''']]
  
 
'''This page were made by [[Contributors|Tri Phan]]'''
 
'''This page were made by [[Contributors|Tri Phan]]'''

Revision as of 07:25, 15 August 2020

Integrals of Exponential Functions

 Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle u}
 be a differentiable function of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x}
, then
 Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int e^x dx=e^x+C}

 
 Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \int e^u \frac{du}{dx}dx=\int e^u du=e^u+C}

Return to Topics Page

This page were made by Tri Phan