Difference between revisions of "Math 22 Logarithmic Functions"
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2.<math>e^{\ln x}=x</math> | 2.<math>e^{\ln x}=x</math> | ||
| + | 3.<math>\ln{xy}=\ln{x}+\ln{y}</math> | ||
| + | |||
| + | 4.<math>\ln{\frac{x}{y}}=\ln x - \ln y</math> | ||
| + | |||
| + | 5.<math>\ln{x^n}=n\ln x</math> | ||
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| + | |||
| + | |||
| + | '''Exercises 1''' Use the properties of logarithms to rewrite the expression as the logarithm of a single quantity | ||
| + | |||
| + | '''a)''' <math>\ln(x-2)-\ln(x+2)</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>\ln(x-2)-\ln(x+2)=\ln \frac{x-2}{x+2}</math> | ||
| + | |} | ||
| + | |||
| + | '''b)''' <math>5\ln (x-6)+\frac{1}{2}\ln(5x+1)</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>5\ln(x-6)+\frac{1}{2}\ln(5x+1)=\ln(x-6)^5+\ln[(5x+1)^{\frac{1}{2}}]=\ln [(x-6)^5\sqrt{5x+1}]</math> | ||
| + | |} | ||
| + | |||
| + | '''c)''' <math>3\ln x+2\ln y -4\ln z</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>\ln x^3 + \ln y^2 -\ln z^4=\ln\frac{x^3y^2}{z^4}</math> | ||
| + | |} | ||
| + | |||
| + | '''d)''' <math>7\ln (5x+4)-\frac{3}{2}\ln (x-9)</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>7\ln (5x+4)-\frac{3}{2}\ln (x-9)=\ln (5x+4)^7-\ln (x-9)^{\frac{3}{2}}=\ln\frac{(5x+4)^7}{(x-9)^{\frac{3}{2}}}</math> | ||
| + | |} | ||
| + | |||
| + | '''Exercises 2''' Solve for x. | ||
| + | |||
| + | '''a)''' <math>\ln(2x)=5</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>\ln(2x)=5</math>, so <math>e^5=2x</math>, hence <math>x=\frac{e^5}{2}</math> | ||
| + | |} | ||
| + | |||
| + | '''b)''' <math>5\ln x=3</math> | ||
| + | {| class = "mw-collapsible mw-collapsed" style = "text-align:left;" | ||
| + | !Solution: | ||
| + | |- | ||
| + | |<math>5\ln x=3</math>, so <math>ln {x^5}=3</math>, so <math>e^3=x^5</math>, hence <math>x=\sqrt[5]{e^3}</math> | ||
| + | |} | ||
Latest revision as of 09:44, 11 August 2020
Logarithm Function
The logarithm is defined as if and only if
Definition of the Natural Logarithmic Function
The natural logarithmic function, denoted by , is defined as if and only if
Properties of the Natural Logarithmic Function
Let 1. The domain of is and the range of is 2. The x-intercept of the graph of is 3. The function is continuous, increasing, and one-to-one. 4. and
Inverse Properties of Logarithms and Exponents
1.Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln e^{\sqrt{2}}}
2.Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e^{\ln x}=x}
3.Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln{xy}=\ln{x}+\ln{y}}
4.Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln{\frac{x}{y}}=\ln x - \ln y}
5.Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln{x^n}=n\ln x}
Exercises 1 Use the properties of logarithms to rewrite the expression as the logarithm of a single quantity
a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(x-2)-\ln(x+2)}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(x-2)-\ln(x+2)=\ln \frac{x-2}{x+2}} |
b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 5\ln (x-6)+\frac{1}{2}\ln(5x+1)}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 5\ln(x-6)+\frac{1}{2}\ln(5x+1)=\ln(x-6)^5+\ln[(5x+1)^{\frac{1}{2}}]=\ln [(x-6)^5\sqrt{5x+1}]} |
c) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3\ln x+2\ln y -4\ln z}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln x^3 + \ln y^2 -\ln z^4=\ln\frac{x^3y^2}{z^4}} |
d) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 7\ln (5x+4)-\frac{3}{2}\ln (x-9)}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 7\ln (5x+4)-\frac{3}{2}\ln (x-9)=\ln (5x+4)^7-\ln (x-9)^{\frac{3}{2}}=\ln\frac{(5x+4)^7}{(x-9)^{\frac{3}{2}}}} |
Exercises 2 Solve for x.
a) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(2x)=5}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(2x)=5} , so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e^5=2x} , hence Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=\frac{e^5}{2}} |
b) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 5\ln x=3}
| Solution: |
|---|
| Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 5\ln x=3} , so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ln {x^5}=3} , so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e^3=x^5} , hence Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=\sqrt[5]{e^3}} |
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