Difference between revisions of "Math 22 Differentials and Marginal Analysis"
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− | |Notice: <math>y=x(1.25+0.02\sqrt{x})=1.25x+0.02x\sqrt{x}=1.25x+0.02x^{\frac{3}{2}}</math>, so <math>dy=f'(x)dx=1. | + | |Notice: <math>y=x(1.25+0.02\sqrt{x})=1.25x+0.02x\sqrt{x}=1.25x+0.02x^{\frac{3}{2}}</math>, so <math>dy=f'(x)dx=[1.25+0.02(\frac{3}{2})x^{\frac{1}{2}}]dx=[1.25+0.03\sqrt{x}]dx</math> |
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Latest revision as of 07:00, 10 August 2020
Differentials
Let represent a differentiable function. The differential of (denoted by ) is any nonzero real number. The differential of (denoted by ) is .
Example: 1) Consider the function . Find when and
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Notice: , so |
2) Find of each function below:
a)
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Notice: , so |
b)
Solution: |
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Notice: , so |
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