Difference between revisions of "Math 22 Differentials and Marginal Analysis"

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   is any nonzero real number. The differential of <math>y</math> (denoted by ) is <math>dy=f'(x) dx</math>.
 
   is any nonzero real number. The differential of <math>y</math> (denoted by ) is <math>dy=f'(x) dx</math>.
  
'''Example''': Consider the function <math>f(x)=3x^3</math>. Find <math>dy</math> when <math>x=1</math> and <math>dx=0.01</math>
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'''Example''': '''1)''' Consider the function <math>f(x)=3x^3</math>. Find <math>dy</math> when <math>x=1</math> and <math>dx=0.01</math>
  
 
{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
 
{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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|Notice: <math>f(x)=3x^3</math>, so <math>dy=f'(x)dx=9x^2 dx=9(1)^2.(0.01)=0.09</math>
 
|Notice: <math>f(x)=3x^3</math>, so <math>dy=f'(x)dx=9x^2 dx=9(1)^2.(0.01)=0.09</math>
 
|}
 
|}
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'''2)''' Find <math>dy</math> of each function below:
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'''a)''' <math>y=\frac{5x+7}{15}</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|Notice: <math>y=\frac{5x+7}{15}=\frac{5x}{15}+\frac{7}{15}</math>, so
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|-
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|<math>dy=f'(x)dx=\frac{5}{15}=\frac{1}{3} dx</math>
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|}
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'''b)''' <math>y=x(1.25+0.02\sqrt{x})</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|Notice: <math>y=x(1.25+0.02\sqrt{x})=1.25x+0.02x\sqrt{x}=1.25x+0.02x^{\frac{3}{2}}</math>, so <math>dy=f'(x)dx=[1.25+0.02(\frac{3}{2})x^{\frac{1}{2}}]dx=[1.25+0.03\sqrt{x}]dx</math>
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|}
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[[Math_22| '''Return to Topics Page''']]
 
[[Math_22| '''Return to Topics Page''']]
  
 
'''This page were made by [[Contributors|Tri Phan]]'''
 
'''This page were made by [[Contributors|Tri Phan]]'''

Latest revision as of 07:00, 10 August 2020

Differentials

 Let  represent a differentiable function. The differential of  (denoted by )
 is any nonzero real number. The differential of  (denoted by ) is .

Example: 1) Consider the function . Find when and

Solution:  
Notice: , so

2) Find of each function below:

a)

Solution:  
Notice: , so

b)

Solution:  
Notice: , so

Return to Topics Page

This page were made by Tri Phan