Difference between revisions of "Math 22 Functions"

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So, <math>(f\circ g)(x)=f(g(x))=f(x^2+3)=2(x^2+3)+1=2x^2+7</math>
 
So, <math>(f\circ g)(x)=f(g(x))=f(x^2+3)=2(x^2+3)+1=2x^2+7</math>
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'''Exercises''' Given <math>f(x)=3x-2</math> and <math>g(x)=2x^2-1</math>. Find each composite function below
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'''1)''' <math>(f\circ g)(x)</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|<math>f(g(x))=f(2x^2-1)=3(2x^2-1)-2=6x^2-5</math>
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|}
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'''2)''' <math>(g\circ f)(x)</math>
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{| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
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!Solution: &nbsp;
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|-
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|<math>g(f(x))=g(3x-2)=2(3x-2)^2-1</math>
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|-
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|}
  
 
==Notes:==
 
==Notes:==

Revision as of 10:00, 12 July 2020

Basic Definitions

A function is a relationship between two variables such that to each value of the independent variable there corresponds exactly one value of the dependent variable.

The domain of the function is the set of all values of the independent variable for which the function is defined.

The range of the function is the set of all values taken on by the dependent variable.

Function notation: We usually denote a function f of x as . For example, function can be written as in function notation.

Exercises Find the domain and range of the following functions:

1)

Solution:  
The domain is where the function defines (or all possible values of x). So, the radicand (everything under the square root) need to be non-negative.
So,
Answer: or
The range is all of possible outcomes (values of y). Notice that is never negative. So is never negative.
Answer: or

Evaluate a Function

To evaluate a function at . We just need to plug in to find .

Example: Find the value of the function at

Answer:

Exercises Find the value of the function at the given values:

2) at

Solution:  
isn't in the domain of . So, undefined
OR

Composite Function

Let and be functions. The function given by is the composite function of and .

Examples: Let and

So,

Exercises Given and . Find each composite function below

1)

Solution:  

2)

Solution:  

Notes:

This page were made by Tri Phan