Difference between revisions of "009A Sample Midterm 2, Problem 2"
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(Created page with "<span class="exam">The function <math style="vertical-align: -5px">f(x)=3x^7-8x+2</math> is a polynomial and therefore continuous everywhere. <span class="exam">(...") |
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| − | |Since <math style="vertical-align: - | + | |Since <math style="vertical-align: -5px">y=0</math> is between <math style="vertical-align: -5px">f(0)=2</math> and <math style="vertical-align: -5px">f(1)=-3,</math> |
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|the Intermediate Value Theorem tells us that there is at least one number <math style="vertical-align: -1px">x</math> | |the Intermediate Value Theorem tells us that there is at least one number <math style="vertical-align: -1px">x</math> | ||
Revision as of 18:33, 13 April 2017
The function is a polynomial and therefore continuous everywhere.
(a) State the Intermediate Value Theorem.
(b) Use the Intermediate Value Theorem to show that has a zero in the interval
| Foundations: |
|---|
| What is a zero of the function |
| A zero is a value such that |
Solution:
| (a) |
|---|
| Intermediate Value Theorem |
| If is continuous on a closed interval |
| and is any number between and |
|
then there is at least one number in the closed interval such that |
(b)
| Step 1: |
|---|
| First, is continuous on the interval since is continuous everywhere. |
| Also, |
|
|
| and
. |
| Step 2: |
|---|
| Since is between and |
| the Intermediate Value Theorem tells us that there is at least one number |
| such that |
| This means that has a zero in the interval |
| Final Answer: |
|---|
| (a) See solution above. |
| (b) See solution above. |