Difference between revisions of "009A Sample Final 1, Problem 4"

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:<math>\frac{dy}{dx}=2x-\sin(\pi(x^2+1))(2\pi x)</math>
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&nbsp;&nbsp; <math>\frac{dy}{dx}=2x-\sin(\pi(x^2+1))(2\pi x)</math>
 
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:<math>y=2(x-1)+2</math>
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&nbsp;&nbsp; <math>y=2(x-1)+2</math>
 
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[[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']]
 
[[009A_Sample_Final_1|'''<u>Return to Sample Exam</u>''']]

Revision as of 15:14, 18 April 2016

If

Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle y=x^{2}+\cos(\pi (x^{2}+1))}

compute    and find the equation for the tangent line at Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle x_{0}=1} . You may leave your answers in point-slope form.

Foundations:  
1. What two pieces of information do you need to write the equation of a line?
You need the slope of the line and a point on the line.
2. What does the Chain Rule state?
For functions   and   Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle ~{\frac {d}{dx}}(f(g(x)))=f'(g(x))g'(x).}

Solution:

Step 1:  
First, we compute  We get
Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {dy}{dx}}\,=\,2x-\sin(\pi (x^{2}+1))(2\pi x).}
Step 2:  
To find the equation of the tangent line, we first find the slope of the line.
Using   in the formula for    from Step 1, we get
Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle m=2(1)-\sin(2\pi )2\pi \,=\,2.}
To get a point on the line, we plug in   into the equation given.
So, we have
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=1^2+\cos(2\pi)=2.}
Thus, the equation of the tangent line is
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=2(x-1)+2.}
Final Answer:  

   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{dy}{dx}=2x-\sin(\pi(x^2+1))(2\pi x)}

   Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y=2(x-1)+2}

Return to Sample Exam