Difference between revisions of "009B Sample Midterm 2, Problem 3"

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(Created page with "<span class="exam"> Evaluate ::<span class="exam">a) <math style="vertical-align: -14px">\int_1^2\bigg(2t+\frac{3}{t^2}\bigg)\bigg(4t^2-\frac{5}{t}\bigg)~dt</math> ::<span...")
 
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<span class="exam"> Evaluate
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<span class="exam"> Evaluate:
  
 
::<span class="exam">a) <math style="vertical-align: -14px">\int_1^2\bigg(2t+\frac{3}{t^2}\bigg)\bigg(4t^2-\frac{5}{t}\bigg)~dt</math>  
 
::<span class="exam">a) <math style="vertical-align: -14px">\int_1^2\bigg(2t+\frac{3}{t^2}\bigg)\bigg(4t^2-\frac{5}{t}\bigg)~dt</math>  

Revision as of 09:17, 3 February 2016

Evaluate:

a)
b)


Foundations:  
Review -substitution

Solution:

(a)

Step 1:  
We multiply the product inside the integral to get
   Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{2}{\bigg (}2t+{\frac {3}{t^{2}}}{\bigg )}{\bigg (}4t^{2}-{\frac {5}{t}}{\bigg )}~dt=\int _{1}^{2}{\bigg (}8t^{3}-10+12-{\frac {15}{t^{3}}}{\bigg )}~dt=\int _{1}^{2}(8t^{3}+2-15t^{-3})~dt} .
Step 2:  
We integrate to get
   .
We now evaluate to get
   Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{2}{\bigg (}2t+{\frac {3}{t^{2}}}{\bigg )}{\bigg (}4t^{2}-{\frac {5}{t}}{\bigg )}~dt=2(2)^{4}+2(2)+{\frac {15}{2(2)^{2}}}-{\bigg (}2+2+{\frac {15}{2}}{\bigg )}=36+{\frac {15}{8}}-4-{\frac {15}{2}}={\frac {211}{8}}} .

(b)

Step 1:  
We use -substitution. Let Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle u=x^{4}+2x^{2}+4} . Then, and Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {du}{4}}=(x^{3}+x)dx} . Also, we need to change the bounds of integration.
Plugging in our values into the equation , we get and .
Therefore, the integral becomes  .
Step 2:  
We now have:
   Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{2}(x^{3}+x){\sqrt {x^{4}+2x^{2}+4}}~dx={\frac {1}{4}}\int _{4}^{28}{\sqrt {u}}~du=\left.{\frac {1}{6}}u^{\frac {3}{2}}\right|_{4}^{28}={\frac {1}{6}}(28^{\frac {3}{2}}-4^{\frac {3}{2}})={\frac {1}{6}}(({\sqrt {28}})^{3}-({\sqrt {4}})^{3})={\frac {1}{6}}((2{\sqrt {7}})^{3}-2^{3})} .
So, we have
   Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{0}^{2}(x^{3}+x){\sqrt {x^{4}+2x^{2}+4}}~dx={\frac {28{\sqrt {7}}-4}{3}}} .
Final Answer:  
(a)  
(b)  

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