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	<title>Systems of Nonlinear Equations - Revision history</title>
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	<updated>2026-04-22T22:02:36Z</updated>
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		<id>https://wiki.math.ucr.edu/index.php?title=Systems_of_Nonlinear_Equations&amp;diff=1191&amp;oldid=prev</id>
		<title>MathAdmin: Created page with &quot;&lt;div class=&quot;noautonum&quot;&gt;__TOC__&lt;/div&gt; ==Comparison to linear systems==  Systems of nonlinear equations are solved using the same methods we used to solve linear systems, elimin...&quot;</title>
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		<updated>2015-11-29T21:14:02Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;lt;div class=&amp;quot;noautonum&amp;quot;&amp;gt;__TOC__&amp;lt;/div&amp;gt; ==Comparison to linear systems==  Systems of nonlinear equations are solved using the same methods we used to solve linear systems, elimin...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;&amp;lt;div class=&amp;quot;noautonum&amp;quot;&amp;gt;__TOC__&amp;lt;/div&amp;gt;&lt;br /&gt;
==Comparison to linear systems==&lt;br /&gt;
&lt;br /&gt;
Systems of nonlinear equations are solved using the same methods we used to solve linear systems, elimination and substitution.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==Solving by substitution (example)==&lt;br /&gt;
&lt;br /&gt;
Solve the following system of equations: &amp;lt;math&amp;gt;3x - y = -2 \text{ and } 2x^2 - y = 0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
Using the first equation, we see that y = 3x + 2. Substituting 3x + 2 for y in the second equation we see that &amp;lt;math&amp;gt; 2x^2 - (3x + 2) = 0&amp;lt;/math&amp;gt;&lt;br /&gt;
Now we can solve for x, by using the quadratic formula, or factoring. We find that &amp;lt;math&amp;gt; (2x + 1)(x - 2) = 0&amp;lt;/math&amp;gt; or that &amp;lt;math&amp;gt; x = \frac{-1}{2}, 2&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Solving back for y, we find that the two points on both curves are &amp;lt;math&amp;gt;(\frac{-1}{2}, \frac{1}{2}), \text{ and }(2, 8)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
==Solving by elimination(example)==&lt;br /&gt;
&lt;br /&gt;
Solve the following system by elimination: &amp;lt;math&amp;gt;x^2 + y^2 = 13 \text{ and }x^2 - y = 7&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Solution:&lt;br /&gt;
&lt;br /&gt;
We can subtract the second equation form the first to get &amp;lt;math&amp;gt; y^2 + y = 6&amp;lt;/math&amp;gt;. We can solve this equation for y to find that y = 2 or -3. For each value of y, we have&lt;br /&gt;
2 values for x. So we have four points of intersection &amp;lt;math&amp;gt;(\pm 3, 2), (\pm 2, -3)&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
  [[Math_5|'''Return to Topics Page]]&lt;/div&gt;</summary>
		<author><name>MathAdmin</name></author>
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