Math 22 Graph of Equation - Revision history

Tphan046 at 14:50, 19 July 2020

2020-07-19T14:50:24Z

2020-07-19T14:50:06Z

2020-07-13T16:58:00Z

Intercepts of a Graph

2020-07-13T16:02:31Z

Points of Intersection

2020-07-13T16:02:12Z

2020-07-13T15:36:17Z

2020-07-13T15:34:24Z

Circles

2020-07-13T15:33:00Z

Circles

2020-07-13T15:30:45Z

Circles

2020-07-13T15:29:43Z

Circles

← Older revision		Revision as of 14:50, 19 July 2020
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	[[Math_22\| '''Return to Topics Page''']]		[[Math_22\| '''Return to Topics Page''']]
		+
	'''This page were made by [[Contributors\|Tri Phan]]'''		'''This page were made by [[Contributors\|Tri Phan]]'''

← Older revision		Revision as of 14:50, 19 July 2020
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−		+	[[Math_22\| '''Return to Topics Page''']]
	'''This page were made by [[Contributors\|Tri Phan]]'''		'''This page were made by [[Contributors\|Tri Phan]]'''

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    To find <math>y</math>-intercepts, let <math>x</math> be zero and solve the equation for <math>y</math>.
-'''Example''' Find the x-intercepts and y-intercepts of the graph <math>y=x^2-2x</math>
+'''Example''' Find the x-intercepts and y-intercepts of the function <math>y=x^2-2x</math>
 {| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
 !Solution: &nbsp;

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 The order pairs that satisfy both of these equation should have the same <math>y</math> value, so <math>y=2x-1=3x+4</math>
-Then, <math>2x-1=3x+4</math>, therefore <math>x=-5</math>
+Then, <math>2x-1=3x+4</math>
 '''This page were made by [[Contributors|Tri Phan]]'''

← Older revision		Revision as of 16:02, 13 July 2020
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	==Points of Intersection==		==Points of Intersection==
		+
		+	An ordered pair that is a solution of two different equations is called a point of intersection of the graphs of the two equations
		+
		+	For example, find the point(s) of intersection of two equations <math>y=2x-1</math> and <math>y=3x+4</math>.
		+
		+	The order pairs that satisfy both of these equation should have the same <math>y</math> value, so <math>y=2x-1=3x+4</math>
		+
		+	Then, <math>2x-1=3x+4</math>, therefore <math>x=-5</math>
		+
		+

	'''This page were made by [[Contributors\|Tri Phan]]'''		'''This page were made by [[Contributors\|Tri Phan]]'''

← Older revision		Revision as of 15:36, 13 July 2020
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	Distance <math>D</math> between <math>(x_1,y_1)</math> and <math>(x_2,y_2)</math> can be calculated by using <math>D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}</math>		Distance <math>D</math> between <math>(x_1,y_1)</math> and <math>(x_2,y_2)</math> can be calculated by using <math>D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}</math>
		+
		+	==Points of Intersection==

	'''This page were made by [[Contributors\|Tri Phan]]'''		'''This page were made by [[Contributors\|Tri Phan]]'''

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 |So, <math>r=\sqrt{(2-3)^2+(1-4)^2}=\sqrt{1+9}=\sqrt{10}</math>
 |-
-|Now, write the equation of the circle with radius <math>r=\sqrt{10}</math> and center <math>(3,4)</math>
+|Now, write the equation of the circle with radius <math>r=\sqrt{10}</math> and center <math>(3,4)</math> to get:
 |}

@@ Line 63: / Line 63: @@
 |Radius is the distance between the center and a point on the circle. So, radius <math>r</math> is the distance between <math>(2,1)</math> and <math>(3,4)</math>.
 |-
-|So, <math>r=\sqrt{(2-3)^2+(1-4)^2}</math>
+|So, <math>r=\sqrt{(2-3)^2+(1-4)^2}=\sqrt{1+9}=\sqrt{10}</math>
 |}