Math 22 Functions - Revision history

Tphan046: /* Finding Inverse Function */

2020-07-19T14:50:52Z

Finding Inverse Function

2020-07-14T03:15:05Z

Combinations of Functions

2020-07-12T19:15:55Z

Finding Inverse Function

2020-07-12T19:14:20Z

Finding Inverse Function

2020-07-12T19:14:10Z

Finding Inverse Function

2020-07-12T19:13:34Z

Finding Inverse Function

2020-07-12T19:10:34Z

Finding Inverse Function

2020-07-12T19:07:05Z

Finding Inverse Function

2020-07-12T19:06:31Z

Finding Inverse Function

2020-07-12T19:04:02Z

Finding Inverse Function

@@ Line 173: / Line 173: @@
 |Step 4: <math>f^{-1}(x)=\frac {3}{2}(x-1)</math>
 |}
 '''This page were made by [[Contributors|Tri Phan]]'''

@@ Line 63: / Line 63: @@
 <math>f(x)-g(x)=(2x+1)-(x^2+3)=-x^2+2x-2</math>
-<math>f(x)g(x)=(2x+1)(x^2+3)=2x^3+x^2+6x+3=</math>
+<math>f(x)g(x)=(2x+1)(x^2+3)=2x^3+x^2+6x+3</math>
 <math>\frac{f(x)}{g(x)}=\frac {2x+1}{x^2+3}</math>

@@ Line 154: / Line 154: @@
 |Step 3: <math>4y=x+1</math>
 |-
-|<math>     y=\frac {x+1}{4}</math>
+|<span style="display:inline-block; width: 45px;"></span> <math>     y=\frac {x+1}{4}</math>
 |-
 |Step 4: <math>f^{-1}(x)=\frac {x+1}{4}</math>
@@ Line 169: / Line 169: @@
 |Step 3: <math>\frac {3}{2}y=x-1</math>
 |-
-|<math>    y=\frac {3}{2}(x-1)</math>
+|<span style="display:inline-block; width: 45px;"></span><math>    y=\frac {3}{2}(x-1)</math>
 |-
 |Step 4: <math>f^{-1}(x)=\frac {3}{2}(x-1)</math>

@@ Line 154: / Line 154: @@
 |Step 3: <math>4y=x+1</math>
 |-
-|&#9<math>     y=\frac {x+1}{4}</math>
+|<math>     y=\frac {x+1}{4}</math>
 |-
 |Step 4: <math>f^{-1}(x)=\frac {x+1}{4}</math>

@@ Line 154: / Line 154: @@
 |Step 3: <math>4y=x+1</math>
 |-
-|<math>     y=\frac {x+1}{4}</math>
+|&#9<math>     y=\frac {x+1}{4}</math>
 |-
 |Step 4: <math>f^{-1}(x)=\frac {x+1}{4}</math>

@@ Line 159: / Line 159: @@
 |}
-'''2)''' <math>(g\circ f)(x)</math>
+'''2)''' <math>f(x)=\frac {3}{2}x+1</math>
 {| class = "mw-collapsible mw-collapsed" style = "text-align:left;"
 !Solution: &nbsp;
 |-
-|<math>g(f(x))=g(3x-2)=2(3x-2)^2-1</math>
+|Step 1: <math>y=\frac {3}{2}x+1</math>
 |-
+|Step 2: <math>x=\frac {3}{2}y+1</math>
 |}
 '''This page were made by [[Contributors|Tri Phan]]'''

@@ Line 153: / Line 153: @@
 |-
 |Step 3: <math>4y=x+1</math>
+|-
-|<math word-spacing: 30px;>y=\frac {x+1}{4}</math>
+|<math word-spacing: 60px;>y=\frac {x+1}{4}</math>
 |-
 |Step 4: <math>f^{-1}(x)=\frac {x+1}{4}</math>