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	<title>005 Sample Final A, Question 12 - Revision history</title>
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	<updated>2026-04-22T20:00:41Z</updated>
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		<title>MathAdmin: Created page with &quot;''' Question '''  Given that &lt;math&gt;\sec(\theta) = -2&lt;/math&gt; and &lt;math&gt;\tan(\theta) &gt; 0 &lt;/math&gt;, find the exact values of the remaining trig functions.  {| class=&quot;mw-collapsibl...&quot;</title>
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		<updated>2015-06-01T01:26:32Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;#039;&amp;#039;&amp;#039; Question &amp;#039;&amp;#039;&amp;#039;  Given that &amp;lt;math&amp;gt;\sec(\theta) = -2&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\tan(\theta) &amp;gt; 0 &amp;lt;/math&amp;gt;, find the exact values of the remaining trig functions.  {| class=&amp;quot;mw-collapsibl...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;''' Question '''  Given that &amp;lt;math&amp;gt;\sec(\theta) = -2&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\tan(\theta) &amp;gt; 0 &amp;lt;/math&amp;gt;, find the exact values of the remaining trig functions.&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Foundations&lt;br /&gt;
|-&lt;br /&gt;
|1) Which quadrant is &amp;lt;math&amp;gt;\theta&amp;lt;/math&amp;gt; in?&lt;br /&gt;
|-&lt;br /&gt;
|2) Which trig functions are positive in this quadrant?&lt;br /&gt;
|-&lt;br /&gt;
|3) What are the side lengths of the triangle associated to &amp;lt;math&amp;gt;\theta?&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|Answers:&lt;br /&gt;
|-&lt;br /&gt;
|1) &amp;lt;math&amp;gt;\theta&amp;lt;/math&amp;gt; is in the third quadrant. We know it is in the second or third quadrant since &amp;lt;math&amp;gt;\cos&amp;lt;/math&amp;gt; is negative. Since \&amp;lt;math&amp;gt;\tan&amp;lt;/math&amp;gt; is positive &amp;lt;math&amp;gt;\theta&amp;lt;/math&amp;gt; is in the third quadrant.&lt;br /&gt;
|-&lt;br /&gt;
|2) &amp;lt;math&amp;gt;\tan&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\cot&amp;lt;/math&amp;gt; are both positive in this quadrant. All other trig functions are negative.&lt;br /&gt;
|-&lt;br /&gt;
|3) The side lengths are 2, 1, and &amp;lt;math&amp;gt;\sqrt{3}.&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 1:&lt;br /&gt;
|-&lt;br /&gt;
| Since &amp;lt;math&amp;gt;\sec(\theta)=-2&amp;lt;/math&amp;gt;, we have &amp;lt;math&amp;gt;\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{-1}{2}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 2:&lt;br /&gt;
|-&lt;br /&gt;
| We look for solutions to &amp;lt;math&amp;gt;\theta&amp;lt;/math&amp;gt; on the unit circle. The two angles on the unit circle with &amp;lt;math&amp;gt;\cos(\theta)=\frac{-1}{2}&amp;lt;/math&amp;gt; are &amp;lt;math&amp;gt;\theta=\frac{2\pi}{3}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\theta=\frac{4\pi}{3}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|-&lt;br /&gt;
|But, &amp;lt;math&amp;gt;\tan\left(\frac{2\pi}{3}\right)=-\sqrt{3}&amp;lt;/math&amp;gt;. Since &amp;lt;math&amp;gt;\tan(\theta)&amp;gt;0&amp;lt;/math&amp;gt;. we must have &amp;lt;math&amp;gt;\theta=\frac{4\pi}{3}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 3:&lt;br /&gt;
|-&lt;br /&gt;
| The remaining values of the trig functions are &lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\sin(\theta)=\sin\left(\frac{4\pi}{3}\right)=\frac{-\sqrt{3}}{2}&amp;lt;/math&amp;gt;,&lt;br /&gt;
|-&lt;br /&gt;
|  &amp;lt;math&amp;gt;\tan(\theta)=\tan\left(\frac{4\pi}{3}\right)=\sqrt{3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\csc(\theta)=\csc\left(\frac{4\pi}{3}\right)=\frac{-2\sqrt{3}}{3}&amp;lt;/math&amp;gt; and &lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\cot(\theta)=\cot\left(\frac{4\pi}{3}\right)=\frac{\sqrt{3}}{3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Final Answer:&lt;br /&gt;
|-&lt;br /&gt;
| &amp;lt;math&amp;gt;\sin(\theta)==\frac{-\sqrt{3}}{2}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\cos(\theta)=\frac{-1}{2}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\tan(\theta)=\sqrt{3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\csc(\theta)=\frac{-2\sqrt{3}}{3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;\cot(\theta)=\frac{\sqrt{3}}{3}&amp;lt;/math&amp;gt;&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
[[005 Sample Final A|'''&amp;lt;u&amp;gt;Return to Sample Exam&amp;lt;/u&amp;gt;''']]&lt;/div&gt;</summary>
		<author><name>MathAdmin</name></author>
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