<?xml version="1.0"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="en">
	<id>https://wiki.math.ucr.edu/index.php?action=history&amp;feed=atom&amp;title=005_Sample_Final_A%2C_Question_11</id>
	<title>005 Sample Final A, Question 11 - Revision history</title>
	<link rel="self" type="application/atom+xml" href="https://wiki.math.ucr.edu/index.php?action=history&amp;feed=atom&amp;title=005_Sample_Final_A%2C_Question_11"/>
	<link rel="alternate" type="text/html" href="https://wiki.math.ucr.edu/index.php?title=005_Sample_Final_A,_Question_11&amp;action=history"/>
	<updated>2026-04-22T20:00:40Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
	<generator>MediaWiki 1.35.0</generator>
	<entry>
		<id>https://wiki.math.ucr.edu/index.php?title=005_Sample_Final_A,_Question_11&amp;diff=779&amp;oldid=prev</id>
		<title>MathAdmin: Created page with &quot;''' Question '''  Solve the following equation in the interval &lt;math&gt; [0, 2\pi)&lt;/math&gt; &lt;br&gt; &lt;center&gt;&lt;math&gt; \sin^2(\theta) - \cos^2(\theta)=1+\cos(\theta)&lt;/math&gt;&lt;/center&gt;  {| c...&quot;</title>
		<link rel="alternate" type="text/html" href="https://wiki.math.ucr.edu/index.php?title=005_Sample_Final_A,_Question_11&amp;diff=779&amp;oldid=prev"/>
		<updated>2015-06-01T01:25:55Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;#039;&amp;#039;&amp;#039; Question &amp;#039;&amp;#039;&amp;#039;  Solve the following equation in the interval &amp;lt;math&amp;gt; [0, 2\pi)&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt; &amp;lt;center&amp;gt;&amp;lt;math&amp;gt; \sin^2(\theta) - \cos^2(\theta)=1+\cos(\theta)&amp;lt;/math&amp;gt;&amp;lt;/center&amp;gt;  {| c...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;''' Question '''  Solve the following equation in the interval &amp;lt;math&amp;gt; [0, 2\pi)&amp;lt;/math&amp;gt; &amp;lt;br&amp;gt;&lt;br /&gt;
&amp;lt;center&amp;gt;&amp;lt;math&amp;gt; \sin^2(\theta) - \cos^2(\theta)=1+\cos(\theta)&amp;lt;/math&amp;gt;&amp;lt;/center&amp;gt;&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
!Foundations: &lt;br /&gt;
|-&lt;br /&gt;
|1) Which trigonometric identities are useful in this problem?&lt;br /&gt;
|-&lt;br /&gt;
|Answer:&lt;br /&gt;
|-&lt;br /&gt;
|1) &amp;lt;math&amp;gt;\sin^2(\theta)=1-\cos^2(\theta)&amp;lt;/math&amp;gt; and &lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 1:&lt;br /&gt;
|-&lt;br /&gt;
| We need to get rid of the &amp;lt;math&amp;gt;\sin^2(\theta)&amp;lt;/math&amp;gt; term. Since &amp;lt;math&amp;gt;\sin^2(\theta)=1-\cos^2(\theta)&amp;lt;/math&amp;gt;, the equation becomes&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;math&amp;gt;(1-\cos^2(\theta))-\cos^2(\theta)=1+\cos(\theta) &amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 2:&lt;br /&gt;
|-&lt;br /&gt;
| If we simplify and move all the terms to the right hand side, we have &amp;lt;math&amp;gt;0=2\cos^2(\theta)+\cos(\theta)&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 3:&lt;br /&gt;
|-&lt;br /&gt;
| Now, factoring, we have &amp;lt;math&amp;gt;0=\cos(\theta)(2\cos(\theta)+1)&amp;lt;/math&amp;gt;. Thus, either &amp;lt;math&amp;gt;\cos(\theta)=0&amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt;2\cos(\theta)+1=0&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 4:&lt;br /&gt;
|-&lt;br /&gt;
| The solutions to &amp;lt;math&amp;gt;\cos(\theta)=0&amp;lt;/math&amp;gt; in &amp;lt;math&amp;gt; [0, 2\pi)&amp;lt;/math&amp;gt; are &amp;lt;math&amp;gt;\theta=\frac{\pi}{2}&amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt;\theta=\frac{3\pi}{2}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Step 5:&lt;br /&gt;
|-&lt;br /&gt;
| The solutions to &amp;lt;math&amp;gt;2\cos(\theta)+1=0&amp;lt;/math&amp;gt; are angles that satisfy &amp;lt;math&amp;gt;\cos(\theta)=\frac{-1}{2}&amp;lt;/math&amp;gt;. In &amp;lt;math&amp;gt; [0, 2\pi)&amp;lt;/math&amp;gt;, the &lt;br /&gt;
|-&lt;br /&gt;
| solutions are &amp;lt;math&amp;gt;\theta=\frac{2\pi}{3}&amp;lt;/math&amp;gt; or &amp;lt;math&amp;gt;\theta=\frac{4\pi}{3}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;mw-collapsible mw-collapsed&amp;quot; style = &amp;quot;text-align:left;&amp;quot;&lt;br /&gt;
! Final Answer:&lt;br /&gt;
|-&lt;br /&gt;
| The solutions are &amp;lt;math&amp;gt;\frac{\pi}{2},\frac{3\pi}{2},\frac{2\pi}{3},\frac{4\pi}{3}&amp;lt;/math&amp;gt;.&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[005 Sample Final A|'''&amp;lt;u&amp;gt;Return to Sample Exam&amp;lt;/u&amp;gt;''']]&lt;/div&gt;</summary>
		<author><name>MathAdmin</name></author>
	</entry>
</feed>